Borrar filtros
Borrar filtros

Documentation for mean function

1 visualización (últimos 30 días)
L'O.G.
L'O.G. el 11 de Jul. de 2022
Comentada: Stephen23 el 11 de Jul. de 2022
I have a 200×1 cell array where each element is {130×1 double}. I want the mean for all the first elements in the 200 cells, all the second elements, all the third elements, and so on. So in the end the vector should be 130 x 1. This seems to do the trick:
mean([C{:}],2)
But from what I understand of the documentation for mean, the 2 indicates that the average is being taken along each row. But isn't each row the 130 x 1 cell array? I don't want the average of those 130 numbers as I mentioned. Am I just misunderstanding the documentation?
  2 comentarios
Torsten
Torsten el 11 de Jul. de 2022
Editada: Torsten el 11 de Jul. de 2022
C{1} = [4;5;6];
C{2} = [7;8;9];
C{:}
ans = 3×1
4 5 6
ans = 3×1
7 8 9
[C{:}]
ans = 3×2
4 7 5 8 6 9
mean([C{:}],2)
ans = 3×1
5.5000 6.5000 7.5000

Iniciar sesión para comentar.

Respuesta aceptada

Steven Lord
Steven Lord el 11 de Jul. de 2022
You're not taking the mean of the cell array. That construct, [C{:}], creates a comma-separated list from the cell array and concatenates the elements of the list together into a numeric array. See the Concatenation section on that documentation page I linked above for an illustration.
So you're passing a numeric array into mean along with a dimension input. For a picture that may help clarify how the dim input is used, see the description of the dim input argument on the mean documentation page.

Más respuestas (0)

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Productos


Versión

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by