Borrar filtros
Borrar filtros

Please help me code this problems

2 visualizaciones (últimos 30 días)
Brendan Jozwiak
Brendan Jozwiak el 11 de Jul. de 2022
Editada: Torsten el 11 de Jul. de 2022

Respuesta aceptada

Brendan Jozwiak
Brendan Jozwiak el 11 de Jul. de 2022
Editada: Torsten el 11 de Jul. de 2022
syms x y z
%3a
expr_A = x*exp(-y);
expr_A_y = int(expr_A,y,0,log(x));
expr_A_yx = int(expr_A_y,x,0,2*z);
expr_A_yxz = int(expr_A_yx,z,1,2);
integral_a = vpa(expr_A_yxz);
% display results
disp('"Part A"')
"Part A"
fprintf('The result of integral is: %f\n\n',integral_a);
The result of integral is: 1.666667
%3b
expr_B = z/(y+1);
expr_B_x = int(expr_B,x,0,sqrt(1-z^2));
expr_B_xz = int(expr_B_x,z,0,1);
expr_B_xzy = int(expr_B_xz,y,0,1);
integral_b = vpa(expr_B_xzy);
% display results
disp('"Part B"')
"Part B"
fprintf('The result of integral is: %f\n\n',integral_b);
The result of integral is: 0.231049

Más respuestas (1)

Ruchika P Barman
Ruchika P Barman el 11 de Jul. de 2022
It is my understanding that you are trying to write a MATLAB code to solve the problem that you have attached with your question. Please consider going through MATLAB Fundamentals or MATLAB On Ramp course in order to solve this with the help of MATLAB.
You may refer to this documentation on Numerical integration - MATLAB integral - MathWorks India to understand the functions and syntax that you can use.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by