How I could solve the for loop problem?
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I couldn't solve the for loop program. I couldn't find where i make mistake. I couldn't get the answer for TC, TCC
clc
close all
k=50;
c=20;
h=2;
H=2;
w0=20;
w1=0.1;
c0=1;
lambdai = [220 250 280 310 400];
b=[50 70 100 120 130];
M = zeros(length(lambdai));
for i=1:M
C1(i) = lambdai;
rho1(i)= (1-(lambdai(i)./mu));
B1(i)=((b(i).*lambdai(i))./lambda);
q1(i)=sqrt((2.*k.*lambdai(i).*(h+c0.*w1.*the2+b(i)))./((H+c0.*w1.*the2).*rho(i).*b(i)));
v1(i)=-((H+c0.*w1.*the2).*rho(i).*q(i))./((H+c0.*w1.*the2+b(i)));
i=i+1;
end
C
rho
B1
q1
v1
N = zeros(length(q1),length(rho),length(v1));
for j=1:N
TCC(i)=c.*lambdai(i)+((k.*lambdai(i))./q1(i))+((H.*(rho(i).*q1(i)+v1(i)).^2)./(2.*rho(i).*q1(i)))+((b(i).v1(i).^2)./(2.*rho(i).*q1(i)))+c0.*(w0+w1.*((rho(i).*q1(i)+v1(i)).^2)./(2.*rho(i).*q1(i))).* the2
TC(i)=c.*lambdai(i)+c0.*w0.*the2+ sqrt((2.*k.*lambdai(i).*b(i)).*rho(i).*(H+c0.*w1.*the2)./((H+c0.*w1.*the2.*b(i))))
j=j+1;
end
TCC
TC
C1 = sum(C(:));
Q=sum(q(:));
rhoo=sum(rho(:));
V=sum(v(:));
B=sum(B1(:));
TCP= c.*lambda+((k.*lambda)./Q) + (H+c0.*w1.*the2).*((rhoo.*Q+V).^2)./(2.*rhoo.*Q)+((B.*V.^2)./(2.*rhoo.*Q))+c0.*w0.*the2
TCPP=c.*lambda+c0.*w0.*the2+sqrt((2.*k.*lambda.*B.*rhoo.*(H+c0.*w1.*the2))./(H+B+c0.*w1.*the2))
Z=TCPP-TCC
R=(Z./TCC).*100
4 comentarios
KSSV
el 12 de Jul. de 2022
You code is a full of mess with lot of corrections. What exactly you are trying to solve?
We suggest you to go through the basics of MATLAB.
M.Rameswari Sudha
el 12 de Jul. de 2022
KSSV
el 12 de Jul. de 2022
It is because:
M = zeros(length(lambdai));
for i=1:M
What does it mean? M is a matrix, you have used it in loop indexing. So, this loop does not get executed.
M.Rameswari Sudha
el 12 de Jul. de 2022
Respuesta aceptada
Más respuestas (1)
M.Rameswari Sudha
el 12 de Jul. de 2022
0 votos
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