Plotting function with differenting constant

Hi,
I'm pretty unexperienced with Matlab so pls bear with me:
I'm trying to plot the function
y=a/(x+1)-(a-x)^2+x/(x+a)
when a is a vector of
a=[1,2,3,50,300]
so I put it in the loop:
for i=1:length(a)
ai=a(i);
y{i}=@(x) (ai/(x+1)-(ai-x)^2+x/(x+ai));
fplot(y{i});
end
but I get just one graph (of ai=300) and tons of yellow warnings..
any comments?

 Respuesta aceptada

a=[1,2,3];%,50,300]; % using just the first 3 a values, for this demonstration
for i=1:length(a)
ai=a(i);
% y{i}=@(x) (ai/(x+1)-(ai-x)^2+x/(x+ai));
y{i}=@(x) (ai./(x+1)-(ai-x).^2+x./(x+ai)); % using element-wise operations (./ and .^) to vectorize
fplot(y{i});
hold on % using hold on to show multiple lines at once
end

2 comentarios

thanks a lot!
Voss
Voss el 19 de Jul. de 2022
Editada: Voss el 19 de Jul. de 2022
You're welcome!

Iniciar sesión para comentar.

Más respuestas (1)

Torsten
Torsten el 19 de Jul. de 2022
Include the command
hold on
after the line
fplot(y{i});
such that preceeding graphs are not overwritten.

Categorías

Más información sobre Loops and Conditional Statements en Centro de ayuda y File Exchange.

Etiquetas

Preguntada:

el 19 de Jul. de 2022

Editada:

el 19 de Jul. de 2022

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by