How can I convert a vector of 30482x1 (it is the accumulated of 4 measurements of 17 min at 8 hz) to a matrix that has columns of 8160 data.

3 comentarios

30482 does not divide evenly into 8160,
30482/8160
ans = 3.7355
so your intended rule for reorganizing this data is not clear.
Fangjun Jiang
Fangjun Jiang el 26 de Jul. de 2022
reshape()
dpb
dpb el 26 de Jul. de 2022
On top of which, given the statement that "it is ... 4 measurements of 17 min at 8 hz)"
>> mod(30482,4)
ans =
2
>>
so the list isn't a complete set of four.

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dpb
dpb el 26 de Jul. de 2022

0 votos

Given the above problems regarding the number of elements in the vector vis a vis the number of channels (and it can't be there's a timestamp as it's also not divisible by five), the best you can do is something like
N=numel(x); % x is the data vector, determine how long it actually is
nCh=4; % the supposed number of channels/columns
M=N-mod(N,nCh); % how many nCh records there actually are
x=reshape(x(1:M),[],nCh); % keep M samples; reshape() to nCh columns
NB --
>> 8160*4
ans =
32640
>>

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el 26 de Jul. de 2022

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el 26 de Jul. de 2022

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