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help n=12 for I=1:n p(I) =rand p(I) =28×p(I) p(I)=ceil(p(I)) end I need to put constraint on this code must be theres no redanandnt values ..so if n=28 p will be all the numbers from 1:28 but in random
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n=12
for I=1:n
p(I) =rand
p(I) =28×p(I)
p(I)=ceil(p(I))
end
I need to put constraint on this code must be theres no redanandnt values ..so if n=28 p will be all the numbers from 1:28 but in random
1 comentario
Adam
el 10 de Feb. de 2015
Please keep code in the body of the question not in the title. The title should be a short description of the problem.
Also please use the {} Code block to include formatted code.
Respuestas (2)
Star Strider
el 10 de Feb. de 2015
‘I need to put constraint on this code must be theres no redanandnt values ..so if n=28 p will be all the numbers from 1:28 but in random’
The easiest way is to use the randperm function:
n = 12;
p = randperm(n);
5 comentarios
Star Strider
el 10 de Feb. de 2015
@Adam — Thank you for your Comment!
Our friendly randperm appears frequently in Answers. That’s how I learned about it, since I don’t otherwise need to use it that often.
Star Strider
el 10 de Feb. de 2015
Adam
el 10 de Feb. de 2015
Something like this would work:
nums = 1:28;
n = 28;
p = zeros(1,n);
count = numel( nums );
for i = 1:n
idx = randi(count);
p(i) = nums( idx );
nums( idx ) = [];
count = count - 1;
end
Not necessarily the most efficient way of doing it, but it will guarantee uniqueness so long as n is at most 28 (or whatever value you set as the maximum of nums.
2 comentarios
Adam
el 10 de Feb. de 2015
replace:
randi( count )
with
round( rand( count ) * n )
and I think that should give you the correct answer.
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