how can I plot y = (cos(t-2)/4)(rect(t+1)/6 )?
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y = [(1-cos(0.25*(t-2).^2))*rect(t+1,6)]
is it correct way to write tht code ?
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Jan
el 3 de Ag. de 2022
Editada: Jan
el 3 de Ag. de 2022
The brackets [ and ] are the concatenation operator in Matlab. What do you concatenate?
The shown code does not allow to plot anything, so how could it be correct?
What is "rect"? Why do you convert "rect(t+1)/6" to "rect(t+1,6)" ?
"cos(t-2)/4" differs from "1-cos(0.25*(t-2).^2)" also. Very strange.
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Adam Danz
el 3 de Ag. de 2022
is it correct way to write tht code ?
The line of code looks functional without knowing any other details including what rect is.
how can I plot y = (cos(t-2)/4)(rect(t+1)/6 )?
Define t, compute y, and plot(t,y)
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