Applying free space path loss to a SNR formula

I apologise if this question is trivial.

I am trying to apply free space path loss to SNR formula, I'm confused how to apply fspl to the SNR formula with the following parameters. Any help will be much appreciated!

distance=0.02; %distance between ue and eNb in km
F= 10;         %frequency in MHz
No= -174;      %noise in dBm/Hz
P_tx= 43;      %in dBm

Answer 1

[Chunru]

distance=0.02; %distance between ue and eNb in km
F= 10;         %frequency in MHz
No= -174;      %noise in dBm/Hz
PL = 20*log10(distance * 1000)   % one way propagation loss in dB (spherical spreading)

PL = 26.0206

[ahmad]

i'm so sorry, but I still don't understand, how to apply free space path loss to snr formula?

one more, isnt it of the formula for free space path loss is like this?

FSPL(dB)=20log10(d(km))+20log10(f(GHz))+92.45

[Chunru]

You need to check out the formula. It's difficult for us to guess without details of the problem.