# why is my plot not showing lines

1 visualización (últimos 30 días)
Doyouknow el 9 de Sept. de 2022
Comentada: Ankit el 12 de Sept. de 2022
%This script is to solve for the investment of \$50
%with an interest of 1% or 0.01 the equation uses the
% A * (1 + r) .^ n equation of interest with investment
%Script wrote by Doyouknow
format bank
monthlyInvestment = 50; %monthlyInvestment = 50;
interestRate = 0.01; %interestRate = 0.01;
monthEndBalance = 0;
disp('Month Month End Balance')
figure;
for month = 1:12
hold on;
monthEndBalance = monthEndBalance + (monthlyInvestment * (1 + interestRate) .^ month);
fprintf([num2str(month)]), disp(monthEndBalance(:))
plot (month,monthEndBalance,'r.')
title('Plot of Investment') %Testing out to see if i can plot
xlabel('Month (month)') %using the given data so far not
ylabel('Year (monthEndBalance)')
xticks (1:12) %sets the x values to be 1 - 12 to represent the graph
end
##### 0 comentariosMostrar -1 comentarios más antiguosOcultar -1 comentarios más antiguos

Iniciar sesión para comentar.

Ankit el 9 de Sept. de 2022
Editada: Ankit el 12 de Sept. de 2022
Edited on 12.09.2022
Problem in your script is that you are not storing your results, values are updated in your "for loop"
%This script is to solve for the investment of \$50
%with an interest of 1% or 0.01 the equation uses the
% A * (1 + r) .^ n equation of interest with investment
%Script wrote by Doyouknow
format bank
monthlyInvestment = 50; %monthlyInvestment = 50;
interestRate = 0.01; %interestRate = 0.01;
j = 1;
monthEndBalance =zeros(1,12);
prevmonthEndBalance = 0;
disp('Month Month End Balance')
Month Month End Balance
figure;
month = 1:12;
for i = 1:length(month)
monthEndBalance(i) = prevmonthEndBalance + (monthlyInvestment * (1 + interestRate) .^ i);
prevmonthEndBalance = monthEndBalance(i);
fprintf([num2str(month(i)) '-' num2str(monthEndBalance(month(i))) '\n'])
end
1-50.5 2-101.505 3-153.02 4-205.0503 5-257.6008 6-310.6768 7-364.2835 8-418.4264 9-473.1106 10-528.3417 11-584.1252 12-640.4664
plot (month,monthEndBalance);hold on
title('Plot of Investment') %Testing out to see if i can plot
xlabel('Month (month)') %using the given data so far not
ylabel('Year (monthEndBalance)')
xticks (1:12) %sets the x values to be 1 - 12 to represent the graph ##### 3 comentariosMostrar 2 comentarios más antiguosOcultar 2 comentarios más antiguos
Ankit el 12 de Sept. de 2022
@Doyouknow Please check the updated solution.

Iniciar sesión para comentar.

### Más respuestas (1)

chrisw23 el 9 de Sept. de 2022
Each plot call (loop) creates a line with one point. ( debug by look at the Figure.Children.Children property or save the return value of plot() )
This results in a 12×1 Line array and not a single line as you expected. Precalculate your data before plotting or try to use an animated line and add points in your loop.
##### 0 comentariosMostrar -1 comentarios más antiguosOcultar -1 comentarios más antiguos

Iniciar sesión para comentar.

### Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!