Rect function with Array

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kale
kale on 24 Sep 2022
Edited: Matt J on 24 Sep 2022
I would like to write my Rect function and I declared the following input variables:
A = 2; %amplitude
T0 = 3; %period
t = [0:Ts:T0]; %time vector base (Ts = 0.01 = time sampling)
The function I wrote is as follows:
function [y] = rect(T0, A, t)
if t < -T0/2
y = 0;
elseif ((t >= -T0/2) & (t <= T0/2))
y = amplitude;
else y = 0; %if t > T0/2
end
I think the problem is the comparison (in the if and elseif) of the vector t with the scalar T0/2, in fact by putting a breakpoint I seem to have noticed that the comparison of the if is only performed on the first element of t (i.e. 0) .. and not with all the others.
I am asking you to suggest the right syntax to use and also (possibly) tell me if I have got the reasoning behind this function wrong.
I thought of doing a for (or while) loop inside the rect function where I increment t=t+Ts, but I would like to avoid this by using the vector t already declared incremented by Ts (as I did)
Thanks!

Accepted Answer

Matt J
Matt J on 24 Sep 2022
Edited: Matt J on 24 Sep 2022
function [y] = rect(T0, A, t)
y= ((t >= -T0/2) & (t <= T0/2)) * A;
end
  2 Comments
Matt J
Matt J on 24 Sep 2022
Edited: Matt J on 24 Sep 2022
You can use the function to create several pulses and add them together.

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