Minimalization problem LinearConstraint and conjugate gradient optimizer

5 visualizaciones (últimos 30 días)
Problem, input data and equations are described in details in attachment. This matrix is called Ms in the below mentioned equation.
The equation is the function F(ω). Omega (ω) are the seven wages which I’m looking for by minimize values of the second equation. The condition is that ω1 + ω2 + ω3 + ω4 + ω5 + ω6 + ω7 = 1.
When using Scipy.stats, the LinearConstraint and Conjugate gradient optimizer were used.
The obtained results were: 0.20141944, 0.1590185 , 0.13852083, 0.08702209, 0.13283426, 0.14539815, 0.14247747. Sum of these wages equals 1.
I very appreciate if someone help me out to write code or use Optimization tool to obtain these results.The input matrix Ms is in attached file.
Best Regards,
Tomi
  2 comentarios
Torsten
Torsten el 25 de Sept. de 2022
What are you trying to minimize ? What are your constraints ? I don't get it from your decription.
Tomi
Tomi el 26 de Sept. de 2022
Movida: Bruno Luong el 26 de Sept. de 2022
I'm sorry for confusion.
Please see the python code used with Scipy - this code produce the results which I want to write in MatLab script and receive the same results. The second equation is used to minimalize omega wages.
I attached python code.
Best,
Tomi

Iniciar sesión para comentar.

Respuesta aceptada

Torsten
Torsten el 26 de Sept. de 2022
Editada: Torsten el 26 de Sept. de 2022
According to the Python code, F is maximized, not minimized. Change in the below code if appropriate.
M = [0.170543 0.327434 0.174194 0 0.421053 0.307167 0.297659
0.155039 0.504425 0.664516 0.530612 0.102493 0.05802 0.053512
0.255814 0.318584 0.212903 0 0.445983 0.337884 0.311037
0.224806 0.548673 0.664516 0.591837 0.141274 0.068259 0.053512
0.383721 0.389381 0.303226 0 0.573407 0.433447 0.41806
0.360465 0.716814 0.883871 0.755102 0.227147 0.078498 0.073579
0.449612 0.566372 0.36129 0 0.775623 0.573379 0.498328
0.484496 0.920354 0.948387 1 0.265928 0.109215 0.107023
0.375969 0.539823 0.303226 0 0.648199 0.481229 0.438127
0.399225 0.769912 0.716129 0.857143 0.224377 0.102389 0.100334
0.356589 0.39823 0.264516 0 0.717452 0.498294 0.444816
0.391473 0.761062 0.703226 0.795918 0.218837 0.098976 0.09699
0.290698 0.327434 0.251613 0 0.770083 0.518771 0.464883
0.395349 0.761062 0.767742 0.795918 0.207756 0.085324 0.09699
0.352713 0.380531 0.277419 0 0.797784 0.501706 0.501672
0.426357 0.778761 0.870968 0.877551 0.265928 0.112628 0.100334
0.403101 0.336283 0.309677 0 0.761773 0.467577 0.491639
0.468992 0.743363 0.877419 0.897959 0.224377 0.119454 0.090301
0.387597 0.345133 0.341935 0 0.775623 0.518771 0.551839
0.496124 0.787611 0.877419 0.857143 0.263158 0.122867 0.113712
0.333333 0.380531 0.341935 0 0.759003 0.566553 0.585284
0.624031 0.80531 0.780645 0.795918 0.293629 0.12628 0.130435
0.534884 0.40708 0.419355 0 0.894737 0.641638 0.628763
0.786822 0.938053 1 0.632653 0.379501 0.197952 0.120401
0.453488 0.380531 0.419355 0 0.842105 0.607509 0.628763
0.554264 0.876106 0.741935 0.877551 0.254848 0.334471 0.130435
0.639535 0.646018 0.593548 0 1 0.8157 0.73913
0.689922 1 0.735484 0.693878 0.351801 0.337884 0.137124
1 0.867257 0.354839 0 0.617729 1 1
0.546512 0.876106 0.703226 0.877551 0.254848 0.334471 0.130435];
w0 = [1/7;1/7;1/7;1/7;1/7;1/7;1/7];
Aeq = ones(1,7);
beq = 1.0;
lb = zeros(7,1);
ub = ones(7,1);
options = optimset('TolFun',1e-10,'TolX',1e-10);
format long
[w,fval] = fmincon(@(w)fun(w,M),w0,[],[],Aeq,beq,lb,ub,[],options)
Local minimum possible. Constraints satisfied. fmincon stopped because the size of the current step is less than the value of the step size tolerance and constraints are satisfied to within the value of the constraint tolerance.
w = 7×1
0.200081504852845 0.157959395465906 0.137599668689948 0.086444832698773 0.131950619523270 0.144443169868022 0.141520808901237
fval =
-3.039398091210332
function value = fun(w,M)
cM = zeros(7,1);
Mw = M*w;
Mwm = mean(Mw);
Mim = mean(M,1);
for i = 1:7
Mi = M(:,i);
cM(i) = sum((Mi-Mim(i)).*(Mw-Mwm))/sqrt(sum((Mi-Mim(i)).^2)*sum((Mw-Mwm).^2));
end
value = -sum(cM);
end
  2 comentarios
Torsten
Torsten el 28 de Sept. de 2022
Editada: Torsten el 28 de Sept. de 2022
@Tomi comment moved here:
Dear Torsten,
I'm trying to understand code - need some help.
I very appreciate if you could tell me how the cM(i) equation was created?
Best,
Tomi

Iniciar sesión para comentar.

Más respuestas (2)

Tomi
Tomi el 28 de Sept. de 2022
Thank you for your time and help.
I very aprpeciate that.
Best,
Tomi

Tomi
Tomi el 28 de Sept. de 2022
Dear Torsten,
I'm trying to understand code - need some help.
I very appreciate if you could tell me how the cM(i) equation was created?
Best,
Tomi
  5 comentarios
Torsten
Torsten el 29 de Sept. de 2022
Editada: Torsten el 29 de Sept. de 2022
M = [0.170543 0.327434 0.174194 0 0.421053 0.307167 0.297659
0.155039 0.504425 0.664516 0.530612 0.102493 0.05802 0.053512
0.255814 0.318584 0.212903 0 0.445983 0.337884 0.311037
0.224806 0.548673 0.664516 0.591837 0.141274 0.068259 0.053512
0.383721 0.389381 0.303226 0 0.573407 0.433447 0.41806
0.360465 0.716814 0.883871 0.755102 0.227147 0.078498 0.073579
0.449612 0.566372 0.36129 0 0.775623 0.573379 0.498328
0.484496 0.920354 0.948387 1 0.265928 0.109215 0.107023
0.375969 0.539823 0.303226 0 0.648199 0.481229 0.438127
0.399225 0.769912 0.716129 0.857143 0.224377 0.102389 0.100334
0.356589 0.39823 0.264516 0 0.717452 0.498294 0.444816
0.391473 0.761062 0.703226 0.795918 0.218837 0.098976 0.09699
0.290698 0.327434 0.251613 0 0.770083 0.518771 0.464883
0.395349 0.761062 0.767742 0.795918 0.207756 0.085324 0.09699
0.352713 0.380531 0.277419 0 0.797784 0.501706 0.501672
0.426357 0.778761 0.870968 0.877551 0.265928 0.112628 0.100334
0.403101 0.336283 0.309677 0 0.761773 0.467577 0.491639
0.468992 0.743363 0.877419 0.897959 0.224377 0.119454 0.090301
0.387597 0.345133 0.341935 0 0.775623 0.518771 0.551839
0.496124 0.787611 0.877419 0.857143 0.263158 0.122867 0.113712
0.333333 0.380531 0.341935 0 0.759003 0.566553 0.585284
0.624031 0.80531 0.780645 0.795918 0.293629 0.12628 0.130435
0.534884 0.40708 0.419355 0 0.894737 0.641638 0.628763
0.786822 0.938053 1 0.632653 0.379501 0.197952 0.120401
0.453488 0.380531 0.419355 0 0.842105 0.607509 0.628763
0.554264 0.876106 0.741935 0.877551 0.254848 0.334471 0.130435
0.639535 0.646018 0.593548 0 1 0.8157 0.73913
0.689922 1 0.735484 0.693878 0.351801 0.337884 0.137124
1 0.867257 0.354839 0 0.617729 1 1
0.546512 0.876106 0.703226 0.877551 0.254848 0.334471 0.130435];
w0 = [1/7;1/7;1/7;1/7;1/7;1/7;1/7];
Aeq = ones(1,7);
beq = 1.0;
lb = zeros(7,1);
ub = ones(7,1);
options = optimset('TolFun',1e-10,'TolX',1e-10);
Mim = mean(M,1);
fun = @(w) -sum(arrayfun(@(i)sum((M(:,i)-Mim(i)).*(M*w-mean(M*w)))/sqrt(sum((M(:,i)-Mim(i)).^2)*sum((M*w-mean(M*w)).^2)),1:7));
fun = function_handle with value:
@(w)-sum(arrayfun(@(i)sum((M(:,i)-Mim(i)).*(M*w-mean(M*w)))/sqrt(sum((M(:,i)-Mim(i)).^2)*sum((M*w-mean(M*w)).^2)),1:7))
format long
[w,fval] = fmincon(fun,w0,[],[],Aeq,beq,lb,ub,[],options)
Local minimum possible. Constraints satisfied. fmincon stopped because the size of the current step is less than the value of the step size tolerance and constraints are satisfied to within the value of the constraint tolerance.
w = 7×1
0.200081504852845 0.157959395465906 0.137599668689948 0.086444832698773 0.131950619523270 0.144443169868022 0.141520808901237
fval =
-3.039398091210332
Tomi
Tomi el 30 de Sept. de 2022
Thank you very much for your help.
Best,
Tomi

Iniciar sesión para comentar.

Categorías

Más información sobre Linear Programming and Mixed-Integer Linear Programming en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by