Permutation of Boolean function in Matlab

I have the Boolean function f = x0x1 + x1x2 (Between x0 and x1 is And operator and between (x0x1) and (x1x2) is XoR operator) and x0,x1,x2 are logical for example x0=[1 0 1 0] ,...

What I am looking for is the permutations (1, 0, 2) and (0, 2, 1) in the Boolean function above.

It means that I have to get different Boolean functions made up with the permutation. For example finding f=x1x0+x0x2 and f=x0x2+x2x1 from f=x0x1+x1x2 by permutation (1,0,2) and (0,2,1) respectively.

Can anybody help me to write the Matlab code for the permutation of the Boolean function? Thanks in advance.

Answer 1

[ag]

Hi HR,

I understand that you want to evaluate the expression "((x0 & x1) ^ (x1 & x2))" by permuting the values of (x0), (x1), and (x2).

To achieve this, you can concatenate the values of (x0), (x1), and (x2) into a two-dimensional array. Subsequently, you can pass the required arrays according to the specified permutation.

Below is a code snippet that demonstrates this process:

% Assuming x0, x1, and x2 are arrays of logical values
x = [x0; x1; x2];

% Define the permutations
permutations = {[1, 0, 2], [0, 2, 1]}; %since MATLAB requires indices to start from 1, add 1 before accessing the index

% Iterate over each permutation
for i = 1:length(permutations)
    perm = permutations{i};
    % Assuming calcExpression is a function that takes three arrays as input, namely x0, x1, and x2
    result = calcExpression(x(perm(1)+1, :), x(perm(2)+1, :), x(perm(3)+1, :));
    disp(result);
end

Hope this helps!