find Maximum values in intervals of time(each 2000 values)

hi

I have a raw of 240001 values. I want to find Maximum values in every 2000 data with its time index.

u= 1 * 240001

t=1 * 240001

max of u[1-2000]? t index ?

max of u[2001-4000] ? t index?

....

thanks for helping me.

Answer 1

[Star Strider]

It would help to have the data.

Try something like this —

u = randn(1, 24001);
t = 1:numel(u);

r = 2000;
U = zeros(r,ceil(numel(u)/r));
U(1:numel(u)) = u;                                      % 'U' Matrix

T = zeros(r,ceil(numel(t)/r));
T(1:numel(t)) = t;                                      % 'T' Matrix

[max2000,idx] = max(U);

for k = 1:size(U,2)
    t2000(k) = T(idx(k),k);
end

max2000

max2000 = 1×13

3.5442 3.4805 3.3493 3.7120 4.4885 2.9583 2.9585 3.1143 3.7602 3.0909 3.3839 3.2174 1.5598

t2000

t2000 = 1×13

1161 3914 4518 7332 9805 10305 12787 15740 17991 19423 20578 23642 24001

.

[navid jafari]

thanks a lot.

It works.

[Star Strider]

As always, my pleasure!

Answer 2

[Florian Bidaud]

Hi,

I would do something like that

for i = 1:(length(u)-1)/2000
    maxArray(i) = max(u((i-1)*2000+1:i*2000));
end

You'll have to adjust for the last value to include the 240001st value, your last interval would be [238001:240001] instead of [238001:240000]

[navid jafari]

thank you.

but I couldn't use this code for my problem.