Not able to plot probability density distribution.
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I am trying to plot a probability density fucntion of growth factors of a matrix with respect to LU decomposition ; the growth factor is defined as g_f in my code.
The final plot should look like this for 3 values of m (size of matrix), I tried it for m = 8. But the plot does not appear! It only gives a nlank figure! Can someone suggest me what changes I shall do, thanks a lot for your advice and time!

x = 1:1000:1;
pd = makedist('Normal');
pd = makedist('Weibull','A',5,'B',2);
n = 1000;
gf = zeros(n);
for j = 1:n
A = (randi([0,1] , 8));
[L,U] = lu(A);
g_f(j) = max(U)/max(A);
end
pdf_normal = pdf(pd,g_f);
plot(x,pdf_normal,'LineWidth',2)
20 comentarios
Anshuman
el 29 de Oct. de 2022
Torsten
el 30 de Oct. de 2022
It's time that you explain in your own words what you are trying to do.
Your code does not help that much.
@Anshuman Pls check again at your level (It's more subjective rather than Matlab)
x = 0:0.1:2;
pd = makedist('Normal');
%pd = makedist('Weibull','A',5,'B',2);
n=length(x);
gf = zeros(n);
m=[8 16 32];
g_f=zeros(1,n);
for i=1:length(m)
for j = 1:n
A = (randi([0,1],m(i)));
[L,U] = lu(A);
g_f(j) = max(U)/max(A);
end
pdf_normal = pdf(pd,g_f);
plot(x,pdf_normal);
hold on;
end
grid on;
Anshuman
el 30 de Oct. de 2022
Anshuman
el 30 de Oct. de 2022
Anshuman
el 30 de Oct. de 2022
Torsten
el 30 de Oct. de 2022
You create a distribution
pd = makedist('Normal');
but you don't use it anywhere. What's the sense of it ?
Anshuman
el 30 de Oct. de 2022
Anshuman
el 30 de Oct. de 2022
Anshuman
el 30 de Oct. de 2022
Instead of
pdf_normal = pdf(pd,g_f);
try
ksdensity(g_f)
n = 10000;
gf = zeros(n);
for j = 1:n
A = (randi([0,1] , 8));
[L,U] = lu(A);
g_f(j) = max(U(:))/max(A(:));
end
ksdensity(g_f)
Anshuman
el 30 de Oct. de 2022
Anshuman
el 30 de Oct. de 2022
Anshuman
el 30 de Oct. de 2022
Anshuman
el 30 de Oct. de 2022
Torsten
el 30 de Oct. de 2022
I don't know from which kind of distribution the matrix entries in the publication are generated. You choose from a discrete distribution with p(A(i,j) = 0) = p(A(i,j) = 1) = 1/2.
Anshuman
el 30 de Oct. de 2022
Torsten
el 30 de Oct. de 2022
You also use logarithmic scale for the x-axis. This is not the case in the graphics of the publication.
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