How to calculate repeated calculation using LOOP?

1 visualización (últimos 30 días)
Undrakh
Undrakh el 12 de Nov. de 2022
Editada: Karim el 13 de Nov. de 2022
I have 2 tables as below:
NetCh - has 12 column (var1 var2 ... var12) and 9 rows
yPeriod1 - has 1 column and 9 rows
I would like to calculation within each column in NetCh for 12 times and write 12 results (Der1 Der2 .. Der12) in a new table.
Now I have to do by mannually all of them.
Can you please tell me make it small code using LOOP.
NetCh1 = table(NetCh.Var1)
NetCh1.Hangal = (NetCh1{:,1}).*(yPeriod1{:,1})
NetCh1.Haliun = (yPeriod1{:,1}).^2
Tr1 = sum(yPeriod1{:,1})
Br1 = sum(NetCh1{:,1},'omitnan')
Hr1 = sum(NetCh1.Hangal,'omitnan')
Qr1 = sum(NetCh1.Haliun)
Der1 = Br1*Qr1-Tr1*Hr1
NetCh2 = table(NetCh.Var2)
NetCh2.Hangal = (NetCh2{:,1}).*(yPeriod1{:,1})
NetCh2.Haliun = (yPeriod1{:,1}).^2
Tr2 = sum(yPeriod1{:,1})
Br2 = sum(NetCh2{:,1},'omitnan')
Hr2 = sum(NetCh2.Hangal,'omitnan')
Qr2 = sum(NetCh2.Haliun)
Der2 = Br2*Qr2-Tr2*Hr2

Respuesta aceptada

Karim
Karim el 12 de Nov. de 2022
Editada: Karim el 13 de Nov. de 2022
Note that you can add data (e.g. a .mat file) to your question using the paperclip symbol. Without it is is difficult to validate the process.
To give you an idea on how a for loop could look like:
% EDIT, updated the routine after the OP provided example data
NetCh = readtable("https://nl.mathworks.com/matlabcentral/answers/uploaded_files/1190448/NetCh.xlsx")
NetCh = 9×13 table
Var1 Var2 Var3 Var4 Var5 Var6 Var7 Var8 Var9 Var10 Var11 Var12 Var13 ___________ ______ ______ ______ ______ ______ ______ ______ ______ ______ ______ ______ ______ {''x2014''} NaN NaN NaN NaN NaN NaN NaN NaN 394.01 396.81 398.17 401.94 {''x2015''} 395.06 401.02 403.83 403.84 399.69 398.05 396.48 394.69 398.28 400.21 398.83 403.9 {''x2016''} 405.03 407.51 407.61 408.24 406.89 397.07 398.52 402.05 395.93 397.88 398.82 406 {''x2017''} 405.3 407.8 408.44 410.49 409.54 404.08 404.25 403.03 403.75 404.21 404.41 407.65 {''x2018''} 407.82 409.4 410.47 416.56 410.47 410.48 401.97 402.19 400.87 408.06 408.8 409.09 {''x2019''} 411.23 411.56 414.78 416.27 413.51 406.49 406.72 407.75 407.06 409.13 409.92 414.33 {''x2020''} 414.91 417.22 416.72 415.13 417.22 414.55 404.2 399.96 410.46 414.34 413.88 417.01 {''x2021''} 414.92 409.11 417.77 420.33 417.7 415.39 412.6 407.96 410.13 415.54 415.26 417.36 {''x2022''} 426.89 421.19 422.16 424.54 NaN NaN NaN NaN NaN NaN NaN NaN
% skip 1 column as it seems to be the vaiable name
numVar = size(NetCh,2)-1;
yPeriodFor = (1:9)';
% create an array to save the results
Der = zeros(numVar,1);
for i = 1:numVar
% extract the current column
% +1 to skip the first column
currData = NetCh{:,i+1};
% do the processing
Hangal = currData.*yPeriodFor;
Haliun = yPeriodFor.^2;
% evaluate the sum's
Tr = sum(yPeriodFor);
Br = sum(currData,'omitnan');
Hr = sum(Hangal,'omitnan');
Qr = sum(Haliun);
% evaluate and save the result
Der(i) = Br*Qr-Tr*Hr;
end
% display the results
Der
Der = 12×1
1.0e+05 * 1.1619 1.1914 1.1913 1.1940 1.6896 1.6674 1.6668 1.6724 2.6110 2.6242
  3 comentarios
Karim
Karim el 12 de Nov. de 2022
I made an update to the answer, the reason for the error is that the first column contains text... you need to skip this column in the for loop. See the adjusted answer.
Undrakh
Undrakh el 13 de Nov. de 2022
Editada: Undrakh el 13 de Nov. de 2022
Hi Karim,
Thank you a lot. This worked for me. :)
And thank you for your advise

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Productos


Versión

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by