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Add values to a Matrix

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Antonio Jayena
Antonio Jayena el 25 de Mzo. de 2015
Respondida: Andrew Newell el 26 de Mzo. de 2015
Hello!
I have the following code:
p=0;
num=0:1:3;
cont=0;
i=0;
b=0;
n=0;
for k=1:num(end)
cad = [];
cad = 'scope_%d_1.csv';
ss = [];
ss = sprintf(cad,num(k))
s = csvread(ss, 2, 0);
[fil,col]=size(s);
for i=1:fil
if ((s(i,2))< 0.5)&&(s(i+1,2)-(s(i,2))>2)&& p>0
cont=cont+1;
n=s(i, 1);
display(s(i, 1)-b);
p=p-1;
else if ((s(i,2))< 0.5)&&(s(i+1,2)-(s(i,2))>2)&& p==0
cont=cont+1;
display(s(i, 1)-n);
b=s(i, 1);
p=p+1;
else if (cont==25)
p=0;
num=0:1:3;
cont=0;
i=0;
b=0;
n=0;
break
end
end
end
end
end
And my intention is to, (in each iteration of any of both IF loops), save in a M matrix all the values that appears in the display (for all the iterations).
It is possible?
Thank you
  2 comentarios
Andrew Newell
Andrew Newell el 25 de Mzo. de 2015
Hello, Antonio. When you have loops, it's much easier to understand the logic if you indent them, so I have done that for you. See Improve Code Readability.
Having done that, I still find it hard to understand your code or determine what values you want saving in a matrix. I suspect that, where you are writing else if, you really mean elseif. I also suggest that you look at your code in the MATLAB editor and fix all the problems that have an orange underline.
Antonio Jayena
Antonio Jayena el 25 de Mzo. de 2015
Thank you for your help Im new on Matlab. Yes you are right with the elseif problem.
I want to save all the values of all the iterations in a Matrix 1xn (of the IF's loops) of
(s(i, 1)-b)
and
(s(i, 1)-n)
In each iteration

Iniciar sesión para comentar.

Respuestas (1)

Andrew Newell
Andrew Newell el 26 de Mzo. de 2015
If you're trying to collect all the values for the inner loop ( for i=1:fil ), you could try putting
M = [];
above the loop, and replacing
display(s(i, 1)-b);
by
M = [M s(i, 1) - b];
and
display(s(i, 1)-n);
by
M = [M s(i, 1)-n];
It's better if a vector of the correct size is preallocated before the loop starts, but I don't know how large M will be.

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