Optimization of code with double for-loops

I am looking to optimize the following code specifically, and more generally, I am trying to learn optimization techniques in MATLAB for a larger project. The code below is just a snippet example which I am looking to learn techniques and then apply to a larger problem. I am potentially looking at values of L being as high as with four nested loops as opposed to just the two shown below.
Any pointers (or links to decent YouTube video on MATLAB optimization) would be welcomed.
clc; clearvars;
T = 1; Ts = 1e-2; t = 0:Ts:L*T;
L = 2^5;
start_time = clock();
for l = 0:L-1
for q = 0:L-1
flag = (t>=(l-q-1)*T) & (t<=(l-q+1)*T);
partA = (T-abs(t-(l-q)*T));
end
end
elapsed_time = clock();
time = elapsed_time(4)*3600+elapsed_time(5)*60+elapsed_time(6)

4 comentarios

for q = 0:L-1
flag = (t>=(l-q-1)*T) & (t<=(l-q+1)*T);
It looks to me as if you should see discretize and possibly splitapply
Catalytic
Catalytic el 20 de Nov. de 2022
@Howard Wilton You appear to have opened several previous threads on similar subjects to this and abandoned them, without accepting an answer or follow-up discussion. It is better if you not do this, so that contributors can know if the question is to be taken seriously.
Howard Wilton
Howard Wilton el 20 de Nov. de 2022
The questions didn't really hit the answer so i thought i would cast the questions differently.
However, your advice is duly noted and i shall be careful in the future. Thanks.
Howard Wilton
Howard Wilton el 20 de Nov. de 2022
Editada: Howard Wilton el 20 de Nov. de 2022
I have taken the code a bit further and managed to dispense with the nested loops . However, I still need a 1D loop. Performance is substantially improved.
clc; clearvars;
L = 2^8; T = 1; t = 0:0.2:L*T;
start_time = clock();
l = 1:L; q = 1:L;
X = (l(:)-q(:).')*T;
for loop = 1:length(t)
t2(:,:,loop) = t(loop) - X;
end
stop_time = elapsedTime(start_time)
function time = elapsedTime(start_time)
elapsed_time = clock-start_time;
time = elapsed_time(4)*3600+elapsed_time(5)*60+elapsed_time(6);
end
Keen to figure out a way to eliminate the 1D loop and generate a matrix .

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 Respuesta aceptada

Walter Roberson
Walter Roberson el 20 de Nov. de 2022
X = (l(:)-q(:).')*T;
for loop = 1:length(t)
t2(:,:,loop) = t(loop) - X;
end
replace with
t2 = reshape(t, 1, 1, []) - X;

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R2020b

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el 20 de Nov. de 2022

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el 20 de Nov. de 2022

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