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How to make the condition for checking the matrix value ?

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Akash Pal
Akash Pal el 26 de Nov. de 2022
Comentada: Akash Pal el 28 de Nov. de 2022
function [popnew1,mutated] =mutation(A,Pm)
mutated = find(rand(size(A))<Pm);
popnew1 = A;
% Why my this condition is not working
if A(mutated)== 1
popnew1(mutated) = 2-A(mutated);
else
popnew1(mutated) = 1-A(mutated);
end
%
end
Please Help me why my this condition part is not working Where A is 3x8 matrix and Pm=0.1 .
Where is the problem in my condition ?

Respuesta aceptada

VBBV
VBBV el 26 de Nov. de 2022
popnew1 = 2-A(mutated);
  10 comentarios
VBBV
VBBV el 27 de Nov. de 2022
if A(mutated) == 1
popnew1(mutated) = 2-popnew1(mutated); % in place of A put popnew1
else
popnew1(mutated) = 1-popnew1(mutated); % in place of A put popnew1
end
Akash Pal
Akash Pal el 28 de Nov. de 2022
Thank you for your suggestion .

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