drawing a point in the graph
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Respuestas (2)
x = 1:5;
y = 20:24;
plot(x,y,x(3),y(3),'*') % specify a marker symbol * in index 3 of y
please follow this for more information about plot
3 comentarios
Ismita
el 6 de Dic. de 2022
try this approach. I am not sure about his efficiency.
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
[x1equality ia]=find(ismember(t1,t2));
[x3equality ib]=find(ismember(t3,t4));
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g',x1(ia),t1(ia),'*',x3(ib),t3(ib),'*')
Ismita
el 7 de Dic. de 2022
x = 0:0.5:10;
t = (x/2).^2;
abs(x-2*sqrt(t)) %cross-check weether x == 2*sqrt(t)
plot(x, t, '*-')
5 comentarios
Ismita
el 6 de Dic. de 2022
Editada: Walter Roberson
el 6 de Dic. de 2022
Walter Roberson
el 6 de Dic. de 2022
You need to calculate the point of interesection between (x2,t2) and (x4,t4) . Then you can plot() that point, specifying a marker. For example,
plot(interesection_x, intersection_y, 'b*')
Ismita
el 7 de Dic. de 2022
Walter Roberson
el 7 de Dic. de 2022
plot(6.78233, 11.66, 'r*')
It does not matter if there is no exact match for this in the curves, if it is the correct intersection point.
Unless, that is, what you want to do is find the closest point on each of the two curves and mark those close points rather than the intersection point?
Ismita
el 7 de Dic. de 2022
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