How to vectorize this piece of code and why doesn't e come out to be zero though it must come out to be zero because u and b are equal?
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Sadiq Akbar
el 10 de Dic. de 2022
Comentada: Bruno Luong
el 11 de Dic. de 2022
u=[30 50 75 -30 -50 -75];
b=u;
Noise=5;
M = 6;%Constant1
N = 6;%Constant2
d = 0.5;%Constant3
K = length(u)/2; %Constant4
alpha=ones(1,K);%[1 1 1 1 1];
a=zeros(M,K);%aTx
f=zeros(N,K);%fRx
c=zeros(M*N, length(u)-K);% Extended Matrix
%%%%%%%%%%%%%%%%%%%%
% Swapping vector b
%%%%%%%%%%%%%%%%%%%%
[~, ix] = sort(u); % u is my desired vector
[~, ix1(ix)] = sort(b);
b = b(ix1);
%%%%%%%%%%%%%%%%%%%%
% Observed response
%%%%%%%%%%%%%%%%%%%
for i=1:K
for h=1:M
a(h,i)=exp(j*2*pi*(h-1)*d*sind(u(i))); %%%%% a
end
for p=1:N
f(p,i)=exp(j*2*pi*(p-1)*d*sind(u(K+i))); %%%%% f
end
end
for g= 1:K
c(:,g)=kron(a(:,g),f(:,g));% Extended vector
end
yo=c*alpha'; % Observed Response (Noise Free)
yo=awgn(yo,Noise);% Uncomment for Noise consideration
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Estimated response
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
ae=zeros(M,K);
fe=zeros(N,K);
ce=zeros(M*N, length(u)-K);
for i=1:K
for h=1:M
ae(h,i)=exp(j*2*pi*(h-1)*d*sind(b(i))); %%%%% ae
end
for p=1:N
fe(p,i)=exp(j*2*pi*(p-1)*d*sind(b(K+i))); %%%%% fe
end
end
for g= 1:K
ce(:,g)=kron(ae(:,g),fe(:,g));
end
ye=ce*alpha';% Estimated Response
%%%%%%%%%%%%%%%%%
% MSE
%%%%%%%%%%%%%%%%%
e=0.0;
for s=1:M*N
e=e+(abs(yo(s,1)-ye(s,1))).^2;
end
e=e/M*N;
0 comentarios
Respuesta aceptada
Bruno Luong
el 10 de Dic. de 2022
Not tested but this
for i=1:K
for h=1:M
ae(h,i)=exp(j*2*pi*(h-1)*d*sind(b(i))); %%%%% ae
end
for p=1:N
fe(p,i)=exp(j*2*pi*(p-1)*d*sind(b(K+i))); %%%%% fe
end
end
can be replaced by
h=(1:M)';
p=(1:N)';
i=1:K;
br = b(:).';
ae=exp(j*2*pi*(h-1)*d.*sind(br(i)));
fe=exp(j*2*pi*(p-1)*d.*sind(br(K+i)));
And
for g= 1:K
ce(:,g)=kron(ae(:,g),fe(:,g));
end
By
ce = reshape(reshape(ae,K,1,[]).*fe,K,[]);
7 comentarios
Más respuestas (1)
Walter Roberson
el 10 de Dic. de 2022
Editada: Walter Roberson
el 10 de Dic. de 2022
format long g
u=[30 50 75 -30 -50 -75];
b=u;
Noise=5;
M = 6;%Constant1
N = 6;%Constant2
d = 0.5;%Constant3
K = length(u)/2; %Constant4
alpha=ones(1,K);%[1 1 1 1 1];
a=zeros(M,K);%aTx
f=zeros(N,K);%fRx
c=zeros(M*N, length(u)-K);% Extended Matrix
%%%%%%%%%%%%%%%%%%%%
% Swapping vector b
%%%%%%%%%%%%%%%%%%%%
[~, ix] = sort(u); % u is my desired vector
[~, ix1(ix)] = sort(b);
b = b(ix1);
%%%%%%%%%%%%%%%%%%%%
% Observed response
%%%%%%%%%%%%%%%%%%%
for i=1:K
for h=1:M
a(h,i)=exp(j*2*pi*(h-1)*d*sind(u(i))); %%%%% a
end
for p=1:N
f(p,i)=exp(j*2*pi*(p-1)*d*sind(u(K+i))); %%%%% f
end
end
for g= 1:K
c(:,g)=kron(a(:,g),f(:,g));% Extended vector
end
yo=c*alpha'; % Observed Response (Noise Free)
yo=awgn(yo,Noise);% Uncomment for Noise consideration
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Estimated response
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
ae=zeros(M,K);
fe=zeros(N,K);
ce=zeros(M*N, length(u)-K);
for i=1:K
for h=1:M
ae(h,i)=exp(j*2*pi*(h-1)*d*sind(b(i))); %%%%% ae
end
for p=1:N
fe(p,i)=exp(j*2*pi*(p-1)*d*sind(b(K+i))); %%%%% fe
end
end
for g= 1:K
ce(:,g)=kron(ae(:,g),fe(:,g));
end
ye=ce*alpha';% Estimated Response
%%%%%%%%%%%%%%%%%
% MSE
%%%%%%%%%%%%%%%%%
e=0.0;
for s=1:M*N
e=e+(abs(yo(s,1)-ye(s,1))).^2;
end
e=e/(M*N);
e2 = sum( abs(yo - ye).^2 )
yo - ye
3 comentarios
Walter Roberson
el 10 de Dic. de 2022
I thought I had canceled that post...
I do not see any reason why the values should be the same. awgn() applies randomness, but your ye has not had any randomness applied to it (certainly not exactly the same randomness). There is no reason for them to be the same.
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