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Storing a matrix in a file.

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Ankrutee Arora
Ankrutee Arora el 22 de Dic. de 2022
Respondida: dpb el 22 de Dic. de 2022
close all;
location = '/MATLAB Drive/PE/Frames/'; % folder in which your images exists
ds = imageDatastore(location) ; % Creates a datastore for all images in your folder
i=1;
array=zeros(65,1080,1920);
while hasdata(ds)
Img = readimage(ds,i);
%i=i+1;
%Img = read(ds); % read image from datastore
%figure, imshow(img); % creates a new window for each image
%Img = imread('Circle.png'); % real miscroscope image of cells
Img=double(Img(:,:,1));
%% parameter setting
timestep=25; % time step
mu=0.2/timestep; % coefficient of the distance regularization term R(phi)
iter_inner=5;
iter_outer=40;
lambda=5; % coefficient of the weighted length term L(phi)
alfa=15; % coefficient of the weighted area term A(phi)
epsilon=150; % papramater that specifies the width of the DiracDelta function
sigma=1.5; % scale parameter in Gaussian kernel
G=fspecial('gaussian',15,sigma);
Img_smooth=conv2(Img,G,'same'); % smooth image by Gaussiin convolution
[Ix,Iy]=gradient(Img_smooth);
f=Ix.^2+Iy.^2;
g=1./(1+f); % edge indicator function.
% initialize LSF as binary step function
c0=2;
initialLSF=c0*ones(size(Img));
% generate the initial region R0 as a rectangle
initialLSF(1:1080, 1:1920)=-c0;
phi=initialLSF;
figure(1);
mesh(-phi); % for a better view, the LSF is displayed upside down
hold on; contour(phi, [0,0], 'r','LineWidth',2);
title('Initial level set function');
view([-80 35]);
figure(2);
imagesc(Img,[0, 255]); axis off; axis equal; colormap(gray); hold on; contour(phi, [0,0], 'r');
title('Initial zero level contour');
pause(0.5);
potential=2;
if potential ==1
potentialFunction = 'single-well'; % use single well potential p1(s)=0.5*(s-1)^2, which is good for region-based model
elseif potential == 2
potentialFunction = 'double-well'; % use double-well potential in Eq. (16), which is good for both edge and region based models
else
potentialFunction = 'double-well'; % default choice of potential function
end
% start level set evolution
for n=1:iter_outer
phi = drlse_edge(phi, g, lambda, mu, alfa, epsilon, timestep, iter_inner, potentialFunction);
if mod(n,2)==0
figure(2);
imagesc(Img,[0, 255]); axis off; axis equal; colormap(gray); hold on; contour(phi, [0,0], 'r');
end
end
% refine the zero level contour by further level set evolution with alfa=0
alfa=0;
iter_refine = 10;
phi = drlse_edge(phi, g, lambda, mu, alfa, epsilon, timestep, iter_inner, potentialFunction);
finalLSF=phi;
figure(2);
imagesc(Img,[0, 255]); axis off; axis equal; colormap(gray); hold on; contour(phi, [0,0], 'r');
hold on; contour(phi, [0,0], 'r');
str=['Final zero level contour, ', num2str(iter_outer*iter_inner+iter_refine), ' iterations'];
title(str);
pause(1);
figure;
mesh(-finalLSF); % for a better view, the LSF is displayed upside down
hold on; contour(phi, [0,0], 'r','LineWidth',2);
str=['Final level set function, ', num2str(iter_outer*iter_inner+iter_refine), ' iterations'];
title(str);
axis on;
array(i)=finalLSF;
i=i+1;
end
Gives Error:In contour (line 51)
In PE (line 47)
Unable to perform assignment because the left and right sides have a different number of elements.
Error in PE (line 90)
array(i)=finalLSF;

Respuestas (1)

dpb
dpb el 22 de Dic. de 2022
array(i)=finalLSF;
tries to stuff the RHS into a single array location where finalLSF was defined as whatever the result of
phi = drlse_edge(phi, g, lambda, mu, alfa, epsilon, timestep, iter_inner, potentialFunction);
finalLSF=phi;
turns out to be. If, as the comments say, that's something that could be displayed meaningfully with countour, then it's obvious it can't be a single number.
It looks like you've lost track of what your variables mean at this point; use the debugger and set a breakpoint and your logic error will likely become obvious.

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R2022b

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