# Given a big square matrix and some eigenvalues, how to find the corresponding eigenvectors?

6 visualizaciones (últimos 30 días)
yi yang el 2 de En. de 2023
Comentada: yi yang el 4 de En. de 2023
My computer configuration: CPU: 8 cores 4.6GHz, 16GB memory.
I have a big matrix A with size(A) = (3072,3072)
I can get the eigenvalues by doing
v = eig(A)
But my computer dies if I do
[V,D] = eig(A)
I need the corresponding eigenvectors of some of the eigenvalues in v, saying I need 180 eigenvectors, and the corresponding eigenvalues are biggest among v. How to do it?
##### 3 comentariosMostrar 2 comentarios más antiguosOcultar 2 comentarios más antiguos
Bruno Luong el 2 de En. de 2023
Editada: Bruno Luong el 3 de En. de 2023
The eigs command is based on Krylov subspace and it is quite poor and fragile numerically. This kind of warning happens all the time
A=rand(1000);
[V,D]=eig(A,'vector');
[~,is]=sort(abs(D),'descend');
Vs=V(:,is);
Ds=D(is);
[Veigs,Deigs]=eigs(A,10);
Warning: 7 of the 10 requested eigenvalues converged. Eigenvalues that did not converge are NaN.
Deigs=diag(Deigs);
for k=1:size(Veigs,2)
errorD = abs((Ds(k)-Deigs(k))/Ds(k));
errorV = norm(dot(Veigs(:,k),Vs(:,k))/(norm(Veigs(:,k).*norm(Vs(:,k)))))-1;
fprintf('k=%d, errorD = %f, errorV = %f\n', k, errorD, errorV)
end
k=1, errorD = 0.000000, errorV = 0.000000 k=2, errorD = 0.000000, errorV = 0.000000 k=3, errorD = 0.000000, errorV = 0.000000 k=4, errorD = NaN, errorV = 0.000000 k=5, errorD = NaN, errorV = 0.000000 k=6, errorD = 1.229746, errorV = -0.974433 k=7, errorD = 1.940090, errorV = -0.971715 k=8, errorD = 1.995754, errorV = -0.972432 k=9, errorD = 1.965161, errorV = -0.930798 k=10, errorD = NaN, errorV = -0.973482
eig works just fine.
That happens more on the middle of the spectrum when the eigenvalues are dense, creating converging issue of the iterative method.
You can run my code several time, some time eigs works ùost of the time it's not.

Iniciar sesión para comentar.

Christine Tobler el 3 de En. de 2023
Editada: Christine Tobler el 3 de En. de 2023
I wouldn't expect a 3072-by-3072 matrix to be a problem on the machine you describe. Could you try to run the following on your machine?
A = randn(3072, 3072);
% A = A + A'; % if your original matrix is symmetric, please also symmetrize here
[U, D] = eig(A);
I'd like to find out if it's any matrix of this size that's causing an issue, or just your particular one.
##### 3 comentariosMostrar 2 comentarios más antiguosOcultar 2 comentarios más antiguos
yi yang el 4 de En. de 2023
Confirmed. It is my memory problem.
My memory was running at 3200MHz, which is recommended by the manufacture. bluescreen, freezing
Now it is running at 2400MHz, which is my system default. No bluescreen, no freezing.
Thanks guys for helping

Iniciar sesión para comentar.

### Más respuestas (2)

the cyclist el 2 de En. de 2023
You could try to use eigs instead of eig. It allows you to get the largest N eigenvalues and the corresponding eigenvectors.
##### 0 comentariosMostrar -1 comentarios más antiguosOcultar -1 comentarios más antiguos

Iniciar sesión para comentar.

John D'Errico el 2 de En. de 2023
Editada: John D'Errico el 2 de En. de 2023
A = magic(8)
A = 8×8
64 2 3 61 60 6 7 57 9 55 54 12 13 51 50 16 17 47 46 20 21 43 42 24 40 26 27 37 36 30 31 33 32 34 35 29 28 38 39 25 41 23 22 44 45 19 18 48 49 15 14 52 53 11 10 56 8 58 59 5 4 62 63 1
format long g
[V,D] = eig(A); d = diag(D)
d =
260 + 0i 51.8459255872628 + 0i -51.8459255872629 + 0i 3.30788760574535e-15 + 1.120272933028e-14i 3.30788760574535e-15 - 1.120272933028e-14i 6.18932227044616e-15 + 0i 9.94987338090162e-16 + 0i -4.24981561804611e-15 + 0i
Now we wish to solve for the eigenvector, corresponding to one of the eigenvalues, as if we did not know the eigenvector already. In this case, we know it, but we need to check how well we did.
eigenvec = @(A,e,n) [A - e*eye(n);[1,zeros(1,n-1)]]\[zeros(n,1);1];
All I did there was to enforce that the first element of the eigenvector is 1. This arbitrarily scales the eigenvector. But except for rare occasions, when the first element of the corresponding eigenvector would have been exactly zero, this will make the system non-singular.
n = size(A,1);
V1 = eigenvec(A,d(1),n);V1 = V1/norm(V1);
[V(:,1),V1]
ans = 8×2
0.353553390593274 0.353553390593274 0.353553390593273 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274 0.353553390593274
In some cases, the two vectors will differ by a factor of -1, but that should be all.
Honestly what I'm not sure I know is why your computer is failing to compute the eigenvectors. 3024 is a pretty small system these days. My computer did not even make a small hiccup when I try that.
##### 0 comentariosMostrar -1 comentarios más antiguosOcultar -1 comentarios más antiguos

Iniciar sesión para comentar.

### Categorías

Más información sobre Linear Algebra en Help Center y File Exchange.

R2022a

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!