Decimal indexing for arrays in MATLAB

15 visualizaciones (últimos 30 días)
If I have a array of 11 elements, within the range 1 and 2, with a difference of 0.1, i.e, m = 1:0.1:2; to access the value of '1.4000' from the array 'm', the normal procedure is to write 'm(5)'. (index must be an integer)
Can I somehow index 'm(1.4)' and get the value 1.4000? (have a decimal value in the index)
  3 comentarios
Bjorn Gustavsson
Bjorn Gustavsson el 10 de En. de 2023
Sometimes I see 1-D interpolation that way - this require the array to have some simple interpretation of samples of a sufficiently smooth function that the samples in the array can be used to build useful estimates for your "fractional" indices. But indexing is to elements you have.
Yuvarajendra Anjaneya Reddy
Yuvarajendra Anjaneya Reddy el 10 de En. de 2023
Editada: Yuvarajendra Anjaneya Reddy el 10 de En. de 2023
@DGM Sorry for not being descriptive of my issue. I have a mesh grid [X,Y] = ndgrid (1:256, 1:256); and another matrix u = sin(X) + cos (Y); I have interpolated 10 values between every consequtive values in all the matrices.
If I need to access the value 'u' when X = 1.4, and Y = 2.8, i.e, u_interp(1.4, 2.8), then I have trouble, as I will have to create new Indices or run the interp2 command again to access the values. So, I thought decimal indexing would be a way..
[X,Y] = ndgrid (1:256, 1:256);
u = sin(X) + cos (Y);
%Interpolation
[Xq, Yq] = ndgrid(1:(1/10):256, 1:(1/10):256);
F = griddedInterpolant(X, Y, u, 'spline');
u_interp = F(Xq, Yq);

Iniciar sesión para comentar.

Respuesta aceptada

Bjorn Gustavsson
Bjorn Gustavsson el 10 de En. de 2023
Have a look at the help and documentation for griddedInterpolant. That function might be what you're looking for. It creates a function that interpolates over a gridded data. For repeated calls this means that it has kept the structure for interpolation such that you won't redo all the set-up you'd do with repeated calls to interp2 again and again with repeated calls.
HTH
  1 comentario
Yuvarajendra Anjaneya Reddy
Yuvarajendra Anjaneya Reddy el 10 de En. de 2023
@Bjorn Gustavsson Thank you for pointing me to the solution. This is what I was looking for.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Matrix Indexing en Help Center y File Exchange.

Productos


Versión

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by