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i've a problem in this code ... there isn't any output graph .. i don't know why ???
for t=0:.00001:1;
n=n+1;
x1=2.5*cosd(10*pi*t);
x2=2*cosd(8*pi*t);
x1(n)=x1;
x2(n)=x2;
end
plot(t,x1)
hold on
plot(t,x2)
1 comentario
Jan
el 21 de Oct. de 2011
Please use code formatting as explained in the "Markup help" link.
Respuesta aceptada
Más respuestas (5)
Andrei Bobrov
el 21 de Oct. de 2011
t=0:.00001:1;
plot(t,2.5*cosd(10*pi*t))
hold on
plot(t,2*cosd(8*pi*t))
or
plot(t,[2.5*cosd(10*pi*t),2*cosd(8*pi*t)])
1 comentario
Mohammed Anveez
el 16 de Mayo de 2020
even iam facing same issue in plotting

mohamed saber
el 21 de Oct. de 2011
0 votos
AR
el 21 de Mzo. de 2017
How can I plot the my Liklihood function for a large n, say at 100, to show max? fplot did not work.
L_theta=1/16*((1+x1*theta)*(1+x2*theta)*(1+x3*theta)*(1+x4*theta))
fplot(L_theta,[-1,1])
I used the iterative Newton method to solve via convergence to theta_MLE and would like to graphically display this as well.
Anyone have a suggestion?
Thank you.
Pawello85
el 6 de Nov. de 2018
0 votos
Hello. I have a small problem to generate a higher resolution plot.
fs=1000; t=0.075:1/fs:0.225; fi=0; A=0.5; f=10:190/150:200; w=2*pi*f; x=A*cos(w.*t+fi); figure plot(t,x); xlabel('t [s]'); ylabel('Amplitude');
carlos ruiz
el 1 de Dic. de 2019
0 votos
Hello i have s problem with this code i can not plot very well this vector
clc
clear
syms L real
T=[5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25]';%Periodos segundos
d=[5 10 30 50 80 100 200 1000 2000];%Tirante de agua profundidad
w=(2*pi./T).^2;
g=9.81;
for i=1:21
for d=1:9
K=2*pi/L;
f=g*(K)*tanh(K*d(1))-w(i);
Ls(i)=solve(f,'L')
Lss=eval(Ls')
end
end
y=abs(Lss)
grid on
hold on
plot(T,y,'r');
xlabel('Wave period T (sec)'); %Titulo del eje X
ylabel('Wave length'); %Titulo del eje Y
title('The dispersion relationship gives the relationship between wave period and wave length For linear waves in finite water depth d'); %Titulo del gráfico
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