How to find Intersection point of plane and vector/line in 3d
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Hello! Could you please help me why my fucntion does not calculate intersection point I. It gaves me my initial X0, Y0, Z0 coordinate
I used this example
[I ] = planeLocation6(1.5, 3.3371, 0.1820)
function [ I ] = planeLocation6(XBar, YBar, ZBar)
X0 = 1.5;
Y0 = 1.5;
Z0 = 3.0;
Theta0 = 30;
planes(:,:,1) = [0 3 3; 0 0 3; 0 3 0; 0 0 0; 0 0 0];
planes(:,:,2) = [0 0 3; 3 0 3; 0 0 0; 3 0 0; 0 0 0];
planes(:,:,3) = [3 0 3; 3 3 3; 3 0 0; 3 3 0; 3 0 0];
planes(:,:,4) = [3 3 3; 0 3 3; 3 3 0; 0 3 0; 0 3 3];
planes(:,:,5) = [0 3 0; 3 3 0; 0 0 0; 3 0 0; 0 0 0];
planes(:,:,6) = [0 3 3; 3 3 3; 0 0 3; 3 0 3; 0 0 3];
location_plane = 6;
for j=1:6
j==location_plane
plane = planes(:,:,j);
p0 = plane(1,:);
p1 = plane(2,:);
p2 = plane(3,:);
p3 = plane(4,:);
V0 = plane(5,:);
Ri = [X0 Y0 Z0];
Rr = [XBar YBar ZBar];
u = Rr-Ri;
w=Ri-V0;
A = p0-p2;
B = p0-p3;
n=cross(A,B); % normal vector of the Plane
u = Rr-Ri;
w=Ri-V0;
D=dot(n,u);
N=-dot(n,w);
sI = N / D;
I = Ri+ sI.*u;
disp(I);
end
Thank you in advance, BR Aknur
3 comentarios
Rik
el 23 de Feb. de 2023
Your code doesn't actually call the function you linked. Is there a reason why you don't want to use it?
Rik
el 28 de Feb. de 2023
I recovered the removed content from the Google cache (something which anyone can do). Editing away your question is very rude. Someone spent time reading your question, understanding your issue, figuring out the solution, and writing an answer. Now you repay that kindness by ensuring that the next person with a similar question can't benefit from this answer.
Aknur
el 2 de Mayo de 2023
Respuesta aceptada
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