t test ( not sure if my implementation is correct)

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Alexander Guillen
Alexander Guillen el 28 de Feb. de 2023
Comentada: Alexander Guillen el 28 de Feb. de 2023
Suppose that I have two groups, N and R. Each group contains four columns which represent different subjects. For example (hypothetically):
N1 = [1:5]' .... N4 = [1:5]' so that N = { N1,N2,N3,N4}
R1 = [1:5]'.... R4 = [1:5]' so that R = {R1...R4}
Is it possible to enable a loop which which can perform the t-test so that I can avoid this manually:
h = ttest(N1,R1);
.
.
.
h = ttest(N1,R4);
---
h = ttest(N2,R1);
.
.
.
h = ttest(N2,R4); and so on
I understand it may be wrong my implementation of the t-test. But I would like to put into a loop what I just described. Any guidance and help will be appreciated.

Respuesta aceptada

David Hill
David Hill el 28 de Feb. de 2023
N=randi(100,5,4);%your matrix;
R=randi(100,5,4);%your matrix
h=1;
for n=1:4
for r=1:4
H(h)=ttest(N(:,n),R(:,r));
h=h+1;
end
end
H
H = 1×16
0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0
  2 comentarios
Alexander Guillen
Alexander Guillen el 28 de Feb. de 2023
wow thank you
Alexander Guillen
Alexander Guillen el 28 de Feb. de 2023
By any chance, do you know how I can display the columns from N and R which h = 1?

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