How do I properly use the "while", "for", "loop" command in this problem?

Good evening,

I am trying to write a code to determine the time required to complete an operation. Here's the scenario:

I have a column vector (A) = [71.213; 74.499; 79.175; 54.163; 83.008; 52.615]. For this vector, I want to take the first element, and substract a random number between (5,10) from it, until the element gets to zero then the code proceeds to the next element.

However, each time I substract a random number from an element, I want to generate a random number between (2,4), and save (add) to a variable, time (t), and keep adding successively generated random number (time) to this variable (t), until the end of the column vector.

The final displayed result will be time (t). Here's is my code, but it runs non-stop.

A = T(:,1);  %Column vector
B = length(A); %size of column (number of elements)
%H = A(i); %Variable to store remaining harvest, after subtracting 
t = 0; %Variable to store harvest time
%T = randi([2 4]); % time to pick fruit
%W = randi ([5 10]) %Weight of fruit
for i = 1:B;
    H = A(i);
     while H<=A(i);
    H = A(i)- randi ([5 10]);
    t = t + randi([2 4]);
     if H>=A(i);
     end
    disp(t);
     end
end
disp(t)

[VBBV]

One way you can modify the code is below

A =  [71.213; 74.499; 79.175; 54.163; 83.008; 52.615];%Column vector
B = length(A); %size of column (number of elements)
%H = A(i); %Variable to store remaining harvest, after subtracting 
t = 0; %Variable to store harvest time
%T = randi([2 4]); % time to pick fruit
%W = randi ([5 10]) %Weight of fruit
for i = 1:B;
  H = A(i);
   while H<=A(i);
      H = H- randi ([5 10]); % this is causing to run loop non stop
      t = t + randi([2 4]);
   if H<=0;disp(t); break;end
   end
end

    28

    57

    85

   109

   140

   165

Answer 1

[Torsten]

A = [71.213; 74.499; 79.175; 54.163; 83.008; 52.615];  %Column vector
B = length(A); %size of column (number of elements)
%H = A(i); %Variable to store remaining harvest, after subtracting 
t = 0; %Variable to store harvest time
%T = randi([2 4]); % time to pick fruit
%W = randi ([5 10]) %Weight of fruit
for i = 1:B
    H = A(i);
    while H > 0
      H = H - randi([5 10]);
      t = t + randi([2 4]);
    end
end
disp(t)

   170

[Uche]

Thanks!

Answer 2

[Voss]

Maybe something like this:

% A = T(:,1);  %Column vector
A = [71.213; 74.499; 79.175; 54.163; 83.008; 52.615];

B = length(A); %size of column (number of elements)
t = 0; %Variable to store harvest time
for i = 1:B
    H = A(i);
    while H > 0
        H = H - randi([5 10]);
        t = t + randi([2 4]);
    end
end

disp(t);

   167

Note that randi generates random integers. If you want to allow the possibility that the random numbers are not integers, you can use rand instead.

[Uche]

Thanks! Got it

[Voss]

You're welcome!

Answer 3

[Askic V]

A = [71.213; 74.499; 79.175; 54.163; 83.008; 52.615];
B = length(A); %size of column (number of elements)
%H = A(i); %Variable to store remaining harvest, after subtracting 
t = 0; %Variable to store harvest time
%T = randi([2 4]); % time to pick fruit
%W = randi ([5 10]) %Weight of fruit
for i = 1:B
    while A(i) >= 0
        A(i) = A(i)- randi ([5 10]);
        t = t + randi([2 4]);
        disp(t);
    end
end

     4

     7

    10

    13

    15

    19

    22

    24

    26

    30

    33

    37

    39

    41

    45

    48

    51

    53

    56

    60

    64

    68

    70

    74

    76

    80

    83

    85

    87

    90

    92

    94

    96

    98

   102

   104

   107

   109

   111

   113

   116

   119

   121

   125

   127

   129

   133

   137

   141

   144

   148

   152

   156

   159

   161

   164

   167

   171

   175

   177

   179

Would this code be what you want?

A

A = 6×1

-4.7870 -7.5010 -5.8250 -0.8370 -0.9920 -3.3850

[Uche]

Thanks!