I am looking to solve for the three theta's using sys in an array. How should my code look to make this happen. Heres what I have:
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syms theta1 theta2 theta3
eq1 = theta1 == 90-asin((L1-hblock_sub-h_ram-L3*sin(theta2)-L4*sin(theta3))/L5);
eq2 = theta2 == acos(-(L6-L4*cos(theta3)-L5*cos(90-theta1))/L3);
eq3 = theta3 == acos((L6+L3*cos(theta2)-L5*cos(90-theta1))/L4);
sol = solve([eq1 eq2 eq3],[theta1 theta2 theta3]);
hblock = subs(sol.theta1,theta2,theta3);hblock_sub = double(hblock_sub);
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Shushant
el 13 de Mzo. de 2023
From my understanding of your issue, you are trying to solve a set of equations but instead of declaring "theta1", "theta2" and "theta3" separately you want to declare them as part of an array. To accomplish this, you can look through this documentation here. I have tried to implement the same using some random values below.
syms theta [1 3]
L1 = 1;
L2 = 2;
L3 = 3;
L4 = 4;
L5 = 5;
L6 = 6;
hblock_sub = 1;
h_ram = 1;
eq1 = theta1 == 90-asin((L1-hblock_sub-h_ram-L3*sin(theta2)-L4*sin(theta3))/L5);
eq2 = theta2 == acos(-(L6-L4*cos(theta3)-L5*cos(90-theta1))/L3);
eq3 = theta3 == acos((L6+L3*cos(theta2)-L5*cos(90-theta1))/L4);
sol = solve([eq1 eq2 eq3],[theta1 theta2 theta3])
hblock = subs(sol.theta1,theta2,theta3)
hblock_sub = double(hblock_sub)
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