Replace table elements in more than one row
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Davindra Usov el 22 de Mzo. de 2023
I have outputted a vector (V) which contains the row indices of elements in a table (T) that contain the string 'rpm'.
T has 3 columns and I initially set all of the elements in column 3 to zero. I now wish to replace all elements in column 3 that have these row indices (so only row 3 and row 7) with a value of 6. I have tried doing this but it doesn't work:
V = [3;7]; % row indices
for i = 1:numel(V)
T(V(i), 3) = repmat(6, numel(V), 1);
I get an error saying To assign to or create a variable in a table, the number of rows must match the height of the
Cameron el 22 de Mzo. de 2023
You should look into how MATLAB does its indexing. You don't have to loop through the array to change a value. Just do it like this:
T = zeros(10,3); %i just picked 10 rows of data
indx = [3,7];
T(indx,3) = 6
Más respuestas (1)
Cris LaPierre el 22 de Mzo. de 2023
Editada: Cris LaPierre el 22 de Mzo. de 2023
You can, but the code you wrote is trying to replace a single element with a vector, hence the error message.
When you are trying to replace each element with the same value, you do not need to use repmat. Perhaps you are trying to do this?
tb = table(zeros(4,1))
tb.Var1([1 3]) = 6
% you could also use repmat if you want
tb.Var1([2 4]) = repmat(10,2,1)