How can i change color of a specific bin using histogram2 or anything similar

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suppose i have some data which i want to cluster into 3D histogram
x = 100*randn(10000,1);
y = 100*randn(10000,1);
h2 = histogram2(x,y,-100:20:100,-100:20:100,'FaceColor','flat')
h2 =
Histogram2 with properties: Data: [10000×2 double] Values: [10×10 double] NumBins: [10 10] XBinEdges: [-100 -80 -60 -40 -20 0 20 40 60 80 100] YBinEdges: [-100 -80 -60 -40 -20 0 20 40 60 80 100] BinWidth: [20 20] Normalization: 'count' FaceColor: 'flat' EdgeColor: [0.1500 0.1500 0.1500] Show all properties
i want to change the color of a specific bin lets say bin which belongs to row and column 5
i would want something like this:
h2.Cdata(5,5,:) = [1 0 0] % set bin color to red
Unrecognized method, property, or field 'Cdata' for class 'matlab.graphics.chart.primitive.Histogram2'.
but theres no Cdata property

Respuesta aceptada

Adam Danz
Adam Danz el 26 de Mzo. de 2023
One way to do this is to plot a histogram for each group.
rng('default') % For reproducibility of this example
x = 100*randn(10000,1);
y = 100*randn(10000,1);
[N, xEdges, yEdges] = histcounts2(x,y,-100:20:100,-100:20:100);
% Plot group 1
N1 = N;
N1(5,5) = 0;
h0 = histogram2('XBinEdges',xEdges,'YBinEdges',yEdges,'BinCounts',N1,'FaceColor','Flat');
% Plot group 2
N2 = N(5,5);
hold on
h1 = histogram2('XBinEdges',xEdges(4:5),'YBinEdges',yEdges(4:5),'BinCounts',N2,'FaceColor','r');
Another solution may be to use bar3 with a width of 1 but that has the following issues
  • bar3 does not have an x input. Solution is to adjust the x values after plotting.
  • the y input to bar3 defines the center of each bin, not the edge. Solution is to compute the centers.
  • defining colors to individual bars might be tricky since a handle is returned for each row along the x axis
  2 comentarios
daniel mitchell
daniel mitchell el 27 de Mzo. de 2023
thank you this workes perfectly.
Probably it will be a good suggestion for MATLAB to add a property for histogram2 class which will enable modifying colors directly.

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