Question about buffer fuction that used in documentation of Monte Carlo ROC Simulation in Help Center
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When I was reading the example of the Monte Carlo ROC Simulation in Help Center of MathWorks. In the Loop Over Pulses section, there is a buffer function is use, which is
rcv_pulses = buffer(rcv_pulses(matchingdelay+1:end),size(rcv_pulses,1));
where rcv_pulses is a  matrix and matchingdelay equals 19. So, as far as I know the output of the new rcv_pulses is a also matrix with
 matrix and matchingdelay equals 19. So, as far as I know the output of the new rcv_pulses is a also matrix with  matrix. But when I checked the code the  rcv_pulses(matchingdelay+1:end) is a
 matrix. But when I checked the code the  rcv_pulses(matchingdelay+1:end) is a  vector, why after the buffer function, it again becomes a
 vector, why after the buffer function, it again becomes a  matrix? Could anyone help me here and explain how this buffer function works here?
 matrix? Could anyone help me here and explain how this buffer function works here?
 matrix and matchingdelay equals 19. So, as far as I know the output of the new rcv_pulses is a also matrix with
 matrix and matchingdelay equals 19. So, as far as I know the output of the new rcv_pulses is a also matrix with  matrix. But when I checked the code the  rcv_pulses(matchingdelay+1:end) is a
 matrix. But when I checked the code the  rcv_pulses(matchingdelay+1:end) is a  vector, why after the buffer function, it again becomes a
 vector, why after the buffer function, it again becomes a  matrix? Could anyone help me here and explain how this buffer function works here?
 matrix? Could anyone help me here and explain how this buffer function works here?0 comentarios
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