Borrar filtros
Borrar filtros

Plotting functions anf computing gradient

1 visualización (últimos 30 días)
lateef
lateef el 29 de Mzo. de 2023
Comentada: Walter Roberson el 29 de Mzo. de 2023
i am currently trying to plot a function and the compute the graident of f using the jacobian function
Plot the function f (x, y) = x sin(xy) y sin(5y).
Compute the gradient of f in using the jacobian function
my current code is shown below yet im getting erors
f = @(x,y) x*sin(x,y) - y*sin(5*y);
syms x y
jacobian([x*sin(x,y - y*sin(5*y))])
Error using sym/sin
Too many input arguments.
gradient(x*sin(x,y - y*sin(5*y)))

Respuesta aceptada

Walter Roberson
Walter Roberson el 29 de Mzo. de 2023
sin(xy) is sin(x*y) not sin(x,y)
f = @(x,y) x*sin(x*y) - y*sin(5*y);
syms x y
jacobian(f(x,y)).'
ans = 
  2 comentarios
Paul
Paul el 29 de Mzo. de 2023
Is there any advantage/disadvantage to using an anonymous function vs a symfun?
syms x y
f(x,y) = x*sin(x*y) - y*sin(5*y);
jacobian(f(x,y),[x y])
ans = 
Seems to me a symfun (or just a plain sym expression) is more natural ...
Walter Roberson
Walter Roberson el 29 de Mzo. de 2023
In this particular case, I was going by the principal of least change to the original code. An anonymous function can be used with jacobian, and the user used an anonymous function, so I showed the small change to the code the user had created.
Sometimes I adjust user code to be better form, but sometimes I just show the minimal change.
More generally, the anonymous function can be used with purely numeric scalar inputs, producing double output, but a symfun would produce a symbolic output, which might or might not be acceptable to the caller.
The posted anonymous function cannot be used with non-scalar inputs. A symfun would work for this computation with nonscalars

Iniciar sesión para comentar.

Más respuestas (0)

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by