Factorial using a for loop

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Joseph
Joseph el 14 de Abr. de 2023
Comentada: John D'Errico el 14 de Abr. de 2023
I need to write a for loop that calculates the factorial 100
This is the code that I have written. I now need to display the value of 100! and asign it to the variable nf
How could I go about that?
n=100
x=1
for b=1:n
x=x*b
end

Respuestas (2)

Walter Roberson
Walter Roberson el 14 de Abr. de 2023
Editada: Walter Roberson el 14 de Abr. de 2023
n=75;
x=sym(1);
for b=1:n
x=x*b;
end
nf_sym = x
nf_sym = 
24809140811395398091946477116594033660926243886570122837795894512655842677572867409443815424000000000000000000
You will not be able to calculate this accurately using double precision.
format long g
n=75;
x=(1);
for b=1:n
x=x*b;
end
nf = x
nf =
2.48091408113954e+109
double(nf_sym) - nf
ans =
8.34369935906606e+93
That is, the final digits in the pure double precision calculation are not correct compared to calculating exactly and taking double precision afterwards.

Les Beckham
Les Beckham el 14 de Abr. de 2023
Your code works fine (though I would add semicolons to the end of all lines except the for and end to avoid spewing a bunch of stuff to the command window).
Then add this after your existing code to "assign it to the variable nf". Or, you could just replace the x variable with nf.
nf = x
  2 comentarios
Les Beckham
Les Beckham el 14 de Abr. de 2023
Also, if you are just getting started with Matlab, I would highly recommend that you take a couple of hours to go through the free online tutorial: Matlab Onramp
John D'Errico
John D'Errico el 14 de Abr. de 2023
All correct. I would add however, that factorial(100) is NOT representable exactly as a double precision number.
factorial(100)
ans = 9.3326e+157
So only the first 16 decimal digits of that result will be correct.

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