3D plotting with three input an one output.

1 visualización (últimos 30 días)
Osman AKYUREK
Osman AKYUREK el 10 de Mayo de 2023
Respondida: Cris LaPierre el 22 de Mayo de 2023
Hi All,
I have three variables to compute new data like Dt=x^2+y^2+z^2. I want to get a 3D plot to see how Dt change with three variable. My case study is below. Any help will be appreciated.
Best,
OA
clear
close all
Wq=0.55272; % torsional frequency in Hz
Wx=0.50914; % Lateral frequency in x direction (Hz)
Wy=0.51109; % Lateral frequency in w direction (Hz)
Qx=Wq/Wx; % frequency ratio
Qy=Wq/Wy; % frequency ratio
ex=0.204; % geometric eccentricity in x direction
ey=0.204; % geometric eccentricity in y direction
e=sqrt(ex^2+ey^2); % absolute eccentricty
Lx=35; % building dimension in x direction in meter
Ly=35; % building dimension in x direction in meter
rx=Lx/sqrt(12); % radius of gyration in x direction
ry=Ly/sqrt(12); % radius of gyration in y direction
r=sqrt(rx^2+ry^2); % absolute radius of gyration
ref=r+e; % effective radius of gyration
nt=1.134; % nt=(delta max/delta avg)
Ax=(nt/1.2)^2; % torsional irregularity coefffcient Ax=(delta max/1.2delta avg)^2
Lamda=(1.2*sqrt(Ax)-1)/(0.6*sqrt(Ax)); % proposed torsional coeffcient
j=1;
k=1;
l=1;
Lx=1;
Ly=1;
e=0;
for As=0.2:0.1:5
for Ax=0.7:0.1:4;
for e=0:0.1:2;
edx(k,j,l)=(((Qy*(sqrt(((As^-2+1)*(Lx)^2)/12)+e))^2)/Lx)*((1.2*(Ax^0.5)-1)/(0.6*(Ax^0.5)));
edy(k,j,l)=(((Qx*(sqrt(((As^2+1)*(Ly)^2)/12)+e))^2)/Ly)*((1.2*(Ax^0.5)-1)/(0.6*(Ax^0.5)));
ed(k,j,l)=sqrt(edx(k,j,l).^2+edy(k,j,l).^2);
Ass(k,j,l)= As;
Axx(k,j,l)=Ax;
ee(k,j,l)=e;
l=l+1;
end
l=1;
k=k+1;
end
k=1;
j=j+1;
end
figure (1)
isosurface(Ass,Axx,ee,ed,1)
  2 comentarios
Nirupama Nagarathinam
Nirupama Nagarathinam el 22 de Mayo de 2023
What kind of 3D plot are you looking for?
You have used "isosurface" function here and how is the obtained result different from what you are expecting?
Osman AKYUREK
Osman AKYUREK el 22 de Mayo de 2023
Hi,
My variable vectors are 'Ass', 'Axx', and 'ee'. I want to see the change in the 'ed' with colorbar. Can you please help me with that.
Best

Iniciar sesión para comentar.

Respuesta aceptada

Cris LaPierre
Cris LaPierre el 22 de Mayo de 2023
If I understand isosurface correctly, you are showing a surface that represents where ed=1 in your volumetric data. For this surface, there will be no variation in color due to ed because the value of ed is the same everywhere on this surface.
Are you instead trying to view the value of ed across your entire volume? If so, that is a 4D problem. You might find this answer helpful.

Más respuestas (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by