A compact way to assign values of a matrix to another matrix

How to assign the values of matrix "x" to the matrix "y" in a, possibly, single line of code?

% Input
x = [3 2 2; 4 5 3; 6 5 4; 4 6 5; 5 6 6; 6 6 7];
y = logical([0 0 0; 1 1 1; 1 1 1; 1 1 1; 1 1 1; 1 1 1; 1 1 1]);

% Desired Output
>> y

Invalid use of operator.

y =
     0     0     0
     3     2     2
     4     5     3
     6     5     4
     4     6     5
     5     6     6
     6     6     7
     
% My attempt
>> y(find(y))=x
y =
  7×3 logical array
   0   0   0
   1   1   1
   1   1   1
   1   1   1
   1   1   1
   1   1   1
   1   1   1

[Torsten]

Could you explain the logic behind this task ?

I would only understand what you are trying to do if x were also 7x3 instead of 6x3 so that the two matrices are compatible in size.

[Sim]

Hi @Torsten, I would like to assign the values of matrix "x" to the "logical 1s" of matrix "y"..... The part of matrix "y" composed solely of "logical 1s" has exactly the same size of matrix "x".....

Obviously, I can assign the values of matrix "x" to the "logical 1s" of matrix "y", only when:

size(x) = size(logical_1s(y))

[Stephen23]

"How to assign the values of matrix "x" to the matrix "y" in a, possibly, single line of code?"

Given that matrix y is of logical type, all non-zero values will be cast into TRUE values. Is that what you want?

[Sim]

@Stephen23, thanks for the comment!! No, I do not want that all non-zero values will be cast into true values. I would like this (I just converted the logical matrix into a numerical matrix):

x = [3 2 2; 4 5 3; 6 5 4; 4 6 5; 5 6 6; 6 6 7];
y = ([0 0 0; 1 1 1; 1 1 1; 1 1 1; 1 1 1; 1 1 1; 1 1 1]);
y(y~=0)=x

y = 7×3

0 0 0 3 2 2 4 5 3 6 5 4 4 6 5 5 6 6 6 6 7

Answer 1

[Dyuman Joshi]

Since y is a logical array, any values assigned to it will be converted to corresponding logical value.

Convert y into double and then assign -

%Modified x, x(1,2) is 0.
x = [3 0 2; 4 5 3; 6 5 4; 4 6 5; 5 6 6; 6 6 7];

y = logical([0 0 0; 1 1 1; 1 1 1; 1 1 1; 1 1 1; 1 1 1; 1 1 1]);
%temporary variable
y1 = y;

%assigning to logical
%You can see how assignment is done to logical array
%0 is assigned as 0 and any other value is 1
y1(y1) = x

y1 = 7×3 logical array
   0   0   0
   1   0   1
   1   1   1
   1   1   1
   1   1   1
   1   1   1
   1   1   1

%convert to double 
z = double(y)

z = 7×3

0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1

%and assign
z(y)=x

z = 7×3

0 0 0 3 0 2 4 5 3 6 5 4 4 6 5 5 6 6 6 6 7

[Sim]

thanks a lot @Dyuman Joshi!! Very clear :-)

Answer 2

[Sim]

Sorry, stupid question... I had a logical matrix "y" and I got what I wanted, just by assigning a numerical array instead of a logical one:

x = [3 2 2; 4 5 3; 6 5 4; 4 6 5; 5 6 6; 6 6 7];
y = ([0 0 0; 1 1 1; 1 1 1; 1 1 1; 1 1 1; 1 1 1; 1 1 1]);
y(y~=0)=x

y = 7×3

0 0 0 3 2 2 4 5 3 6 5 4 4 6 5 5 6 6 6 6 7