delete special characters (\ / : * " < > |) in char

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Alberto Acri
Alberto Acri el 25 de Jun. de 2023
Comentada: Alberto Acri el 26 de Jun. de 2023
Hi. I need to transform these lines:
name_1 = '<Hello World>';
name_2 ='File numb: 5';
into these:
name_1 = 'Hello World';
name_2 ='File numb 5';
In general, I would like to delete, if they are present, within the name all 8 symbols: \ / : * " < > |

Respuesta aceptada

Matt J
Matt J el 25 de Jun. de 2023
One way:
name_1 = '<Hello World>';
pat=num2cell('\/:*"<>|');
name_1=erase(name_1,pat)
name_1 = 'Hello World'

Más respuestas (3)

Matt J
Matt J el 25 de Jun. de 2023
Editada: Matt J el 25 de Jun. de 2023
One way:
name_1 = '<Hello World>';
tf=ismember(name_1, '\/:*"<>|');
name_1(tf)=''
name_1 = 'Hello World'
  1 comentario
Alberto Acri
Alberto Acri el 26 de Jun. de 2023
Thank you for your reply. It is as good as the others' answer.

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Jan
Jan el 25 de Jun. de 2023
name_1 = '<Hello World>';
name_1 = erase(name_1, ["<", ">", "\", "/", ":", "*", """", "|"])
name_1 = 'Hello World'
  1 comentario
Alberto Acri
Alberto Acri el 26 de Jun. de 2023
Thank you for your reply. It is as good as the others' answer.

Iniciar sesión para comentar.


DGM
DGM el 25 de Jun. de 2023
Editada: DGM el 25 de Jun. de 2023
You could also use regexprep(), though perhaps using erase() is more convenient.
% using numbered variables only makes processing more difficult
% instead of embedding implicit indices in the names, just use an array
names = {'<Hello World>';
'File numb: 5';
'1\|2/>3:<4*"5"*6<:7>/8|\9'};
% replace any instance of the listed characters with ''
names = regexprep(names,'[\\/:*"<>|]*','')
names = 3×1 cell array
{'Hello World'} {'File numb 5'} {'123456789' }
  1 comentario
Alberto Acri
Alberto Acri el 26 de Jun. de 2023
Thank you for your reply. It is as good as the others' answer.

Iniciar sesión para comentar.

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R2021b

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