using quiver to create a vector field for an equation with only 1 variable.

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I have an equation which i am trying to use quiver to create a vector field for. the equation can be defined as this. yprime = alpha*y - beta*y.^2 - H where H = ((y.^3)*p)./((y.^3)+q) and alpha and beta are constants. so are p and q. everywhere I look though quiver is used to define problems with two equations. is there a way to use it for this equation?

Respuestas (1)

KSSV
KSSV el 27 de Jun. de 2023
alpha = rand ;
beta = rand ;
p = rand ;
q = rand ;
y = linspace(0,1) ;
yprime = alpha*y - beta*y.^2-(((y.^3)*p)./((y.^3)+q)) ;
dyprime = gradient(yprime) ;
plot(y,yprime)
hold on
quiver(y,yprime,yprime,dyprime)
  2 comentarios
Elijah Jones
Elijah Jones el 27 de Jun. de 2023
Editada: Elijah Jones el 27 de Jun. de 2023
alpha = .75 ;
beta = .1 ;
p = 1.5 ;
q = 1.25 ;
y = linspace(0,1) ;
yprime = alpha*y - beta*y.^2-(((y.^3)*p)./((y.^3)+q)) ;
dyprime = gradient(yprime) ;
plot(y,yprime)
hold on
quiver(y,yprime,yprime,dyprime)
this is the stuff i have to put into this equation. it doesn't look correct. if this makes any difference yprime is also dy/dt. differential equation just doesn't have any t's in it. The direction field should though. I'm looking for the slop field that is y(t) using yprime above.
Elijah Jones
Elijah Jones el 27 de Jun. de 2023
the direction field should be on of a logistic function

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