creat stateflow use script

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wenchao zhang
wenchao zhang el 14 de Ag. de 2023
Comentada: wenchao zhang el 14 de Ag. de 2023
hello,when i run the following script,error happens, any one knows what the root reason, following are the script.
sfnew
rt = sfroot;
ch = find(rt,'-isa','Stateflow.Chart');
st = Stateflow.State(ch);
view(st)
j1 = Stateflow.Junction(ch);
j1.Position.Radius = 16.18;
j1.Position.Center = [31.41 27.18];
j2 = Stateflow.Junction(ch);
j2.Position.Radius = 16.18;
j2.Position.Center = [62.41 27.18];
transition = Stateflow.Transition(ch);
transition.Source = j1;
transition.Destination = j2;
transition.LabelString = '{xx;yy;zz;}';
  2 comentarios
Fangjun Jiang
Fangjun Jiang el 14 de Ag. de 2023
No error in R2022b. What is the error message?
wenchao zhang
wenchao zhang el 14 de Ag. de 2023
ok,thanks,may be it is caused by lost the state flow license, tomorrow i will check again. may be some command not supported in 2019a, not sure

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