Skip multiple iterations in for loop

Is there a way to adjust the "continue" keyword in Matlab so that it skips multiple iterations? For example can I do this?

index=[0 0 0 1 0 0 0 0 0 0];
a=0;

for i=1:10
    if index(i)==1
        continue ("skip next 3 iterations")
    end

      a=a+1
  end

so what I would end up is something like a = 1, 2, 3, 4, 5, 6, 7

Answer 1

[Andrei Bobrov]

index=[0 0 0  0 1 0 0 0 0 0];
a=[];
b = 1;
for i=1:10
    if index(i)==1
        if i==1 || index(i-1)==0
            index(i+[0:2])=1;
        end
        continue
    end
    a=[a b];
    b = b+1;
end

ADD (11:46 MDT 06.12.2011) for reply Matthew (Thank you Matthew!)

1. with loop for..end and continue

a = [];
b = 1;
for i1=1:numel(index)
    if index(i1)==1
        k = 1;
    end
    if k <= 3
       k = k + 1;
       continue
    end
    a=[a b];
    b = b+1;
end

2. without loop

a = 1:numel(setdiff(1:numel(index),unique(bsxfun(@plus,find(index),(0:2)'))))

[Nick]

Oh thanks, I ended up using some if statements as a workaround too but I think your code is a lot cleaner.

[Matthew]

Nice solution, but it doesn't work if index=[0 0 0 0 1 0 0 1 0 0]

Answer 2

[John Kitchin]

This looks like it will do what you want:

index=[0 0 0 1 0 0 0 0 0 0];
a=0;
i = 1;
while i < length(index)
    if index(i) == 1
        i = i+3;
    else
        i = i+1;
    end
    a = a + 1
end

Answer 3

[Image Analyst]

You can do what (I think) you want if you do it like this:

a = 0;
indexesToUse = find(index);
for k = indexesToUse
      fprintf('k = %d\n', k);
      a = a + 1;
end

This would do the loop only for locations where your "index" array was equal to 1. Is that what you're after?

[Jan]

The JIT has some magic power:

a = 0; indexesToUse = logical([0,1,0,1,0]);

for k = 1:n, if indexesToUse(k), <operations>, end, end

This is faster under some conditions.