What is wrong with this code.
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% disp('%% -- Aufgabe 2.2.3 -- %%');
% Gitter erzeugen
[x y]=meshgrid([-2:0.05:2],0);
% Differentialgleichung
dx=x-x.^3;
ylim_extra=[-1/3 -1/3];
% Stabilitätsanalyse, Fixpunkte und zeitlicher Verlauf
[substatusflag,handle]=stabilitaetsanalyse(x,y,dx,zeros(size(y)),[],[],5,ylim_extra);
for i_count=2:4
set(handle(i_count),'XTick',[-2:2])
end
skizze_zeitverlauf(x,dx,5);
hold on % Analytische Lösung
t=0:0.05:2;
for startval=-2:0.25:2
C=(startval)/sqrt(1-startval^2);
plot(0,startval,'o','MarkerFaceColor',[0.75 0 0], ...
'MarkerEdgeColor',[0.75 0 0])
plot(t,exp(t)*C./sqrt(1+exp(2*t)*C^2), ...
'LineWidth',2,'Color',[0.75 0 0])
end
5 comentarios
Dyuman Joshi
el 11 de Sept. de 2023
"Is it possible that you can provide the code in easy way...thanks in advance."
As I mentioned earlier - We can not help you with this. You should ask the author of the code for these functions.
Walter Roberson
el 11 de Sept. de 2023
The author of that code appears to be Dominik Zobel who was at dominik.zobel@tu-harburg.de
They posted code at a server that no longer exists.
Respuestas (1)
Sam Chak
el 11 de Sept. de 2023
Editada: Sam Chak
el 11 de Sept. de 2023
Update: Thanks to @Walter Roberson for finding the source (PDF). The MATLAB functions stabilitaetsanalyse() and skizze_zeitverlauf() are unavailable. However, I tried to duplicate the results on page 3, section 2.2.3.
syms x(t) C
eqn = diff(x,t) == x - x.^3;
cond = x(0) == C; % initial value
xSol = dsolve(eqn, cond);
xSol = simplify(xSol)
c = -2:0.25:2; % range of initial values
for j = 1:numel(c)
xt = subs(xSol, C, c(j));
if c(j) >= 0
fplot( xt, [0 2], 'r'), hold on
else
fplot(-xt, [0 2], 'r'), hold on
end
end
hold off, grid on
xlabel('t')
ylabel('x(t)')
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