Matrix Data Results Explanation
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Augusto Gabriel da Costa Pereira
el 16 de Sept. de 2023
Comentada: Dyuman Joshi
el 16 de Sept. de 2023
I used the following code, and you can see that in the second row of the fourth column, the result is zero and not NaN; it should be NaN as the result.
%
soma_total = nan(3, 4);
data1 = [nan nan 1 2; 1 2 nan nan; 1 2 nan nan];
data2 = [5 5 nan nan; 2 1 1 nan; nan nan 1 1];
%
result = nansum(cat(3, soma_total, data1, data2), 3);
%
disp(result);
The result was:
[5 5 1 2;
3 3 1 0;
1 2 1 1]
The result should be:
[5 5 1 2;
3 3 1 NaN;
1 2 1 1]
Does anyone have an idea to solve this?
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Dyuman Joshi
el 16 de Sept. de 2023
Editada: Dyuman Joshi
el 16 de Sept. de 2023
nansum does not do what you are expecting it to do. Also, using nansum() is not recommended as you can see from its documentation page. Use sum instead -
Here's a workaround -
%
soma_total = nan(3, 4);
data1 = [nan nan 1 2; 1 2 nan nan; 1 2 nan nan];
data2 = [5 5 nan nan; 2 1 1 nan; nan nan 1 1];
%Dimension to operate on
dim = 3;
%defining the array
arr = cat(dim, soma_total, data1, data2);
%Finding indices for all elements which are NaN corresponding to the "dim" dimension
idx = all(isnan(arr),dim)
%If you want to use nansum instead, use this command
%result = nansum(arr,dim)
result = sum(arr,dim,'omitnan')
%Converting the respective values back to NaN
result(idx) = NaN
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