Evaluate double integral using trapezoidal rule

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Mark Johnson
Mark Johnson el 15 de Abr. de 2015
Comentada: Sean de Wolski el 15 de Abr. de 2015
I have an assignment to evaluate a double integral using trapezoidal rule. The first part was to evaluate a double integral using trapezoidal rule with limits 0 <= x <= 2, 0 <= y <= 1
I have a working script for that:
N = 100;
xh= 1.25;
x = linspace(0,2,N);
y = linspace(0,1,0.5*N);
dx = diff(x(1:2));
dy = diff(y(1:2));
[x,y] = meshgrid(x,y);
funk = exp(-10.*((x-xh).^2+y.^2)).*cos(y.*(x-xh));
funk(2:end-1,:) = funk(2:end-1,:)*2;
funk(:,2:end-1) = funk(:,2:end-1)*2;
out = sum(funk(:))*dx*dy/4;
disp(out)
Now for the second part the limits are 0 <= x <= 2, 0 <= y <= ((pi*x)/2)
How do I get y (line 4 in code) to take corresponding x values from the x-matrix to create the y-matrix? If I get that to work I shouldn't have to change anything else in the code right, or am I missing something?

Respuestas (1)

Sean de Wolski
Sean de Wolski el 15 de Abr. de 2015
Editada: Sean de Wolski el 15 de Abr. de 2015
How about instead of re-linspacing:
y = pi*x/2
  2 comentarios
Mark Johnson
Mark Johnson el 15 de Abr. de 2015
How do you mean? Maybe I'm misinterpreting you but won't that give me just one value for y. From my understanding I need a matrix, the same size as x, for y.
Sean de Wolski
Sean de Wolski el 15 de Abr. de 2015
x is a vector (output from linspace) so x multiplied my scalars will also be a vector.
Run it!

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