Dear expert-
I am trying to fill a column and extract some specific rows from a data, I cannot figure out how to do it.
What I want to do is:
1) If row from column H = 0, replace 0 with its corresponding row value from column G.
2) If column G = column S, extract only that row + row before and row after.
Your will be very appriciated.
Thank you

4 comentarios

Dyuman Joshi
Dyuman Joshi el 22 de Oct. de 2023
Editada: Dyuman Joshi el 22 de Oct. de 2023
Use logical indexing for the first part - Find Array Elements That Meet a Condition, Access Data in Tables
(For the 2nd part) It's not clear to me what extract means in this context. Though the approach is similar, compare and get the indices satisfying the comparison via find and get the corresponding indices for the rows before and after by adding and subtracting 1. You will need to check if the indices are within the range of dimensions or not.
Use the indices to extract the data as required.
Sanley Guerrier
Sanley Guerrier el 22 de Oct. de 2023
Movida: Dyuman Joshi el 22 de Oct. de 2023
Thanks, Dyuman
What I mean for example if value in row 5 is the same for column G and S, extract rows 4, 5, and 6.
Dyuman Joshi
Dyuman Joshi el 22 de Oct. de 2023
Yes, I understood that and provided suggestions accordingly.
I specified a flow chart to go through what you want to do, whereas @Voss was kind enough to provide you a full working solution.
Sanley Guerrier
Sanley Guerrier el 22 de Oct. de 2023
Appriciate it!

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 Respuesta aceptada

Voss
Voss el 22 de Oct. de 2023
T = readtable('data.xlsx');
T.Properties.VariableNames = num2cell(char(64+(1:size(T,2))));
% set H = G where H == 0
idx = T.H == 0;
T.H(idx) = T.G(idx);
% extract rows +/- 1 where G == S
idx = T.G == T.S;
idx = any([idx [false; idx(1:end-1)] [idx(2:end); false]],2);
extracted_rows = T(idx,:)
extracted_rows = 12×28 table
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z [ \ ___ _____ ___________ ___________ ______________________ _______ ____ ____ _____ ___ ________ _____ ___ ___________ _____ _______ _____ ___ ____ _____________ _______ _____ ____ _ __ __ __ ________ 107 {'U'} {'0+0.000'} {'0+0.151'} {'2010 RECON BIT' } {'BAB'} 2005 2013 4500 2.9 {'TRAN'} 166 107 {'MN107-U'} {'U'} {'BAB'} 4500 9.4 2004 {0×0 char } {'BAB'} 138.5 0.11 0 6 24 26 {'TRAN'} 107 {'U'} {'0+0.000'} {'0+0.151'} {'2010 RECON BIT' } {'BAB'} 2005 2013 4500 2.9 {'TRAN'} 166 107 {'MN107-U'} {'U'} {'BAB'} 4500 9.4 2005 {'BAB Rural'} {'BAB'} 55 0.05 0 0 0 0 {'TRAN'} 107 {'U'} {'0+0.000'} {'0+0.151'} {'2010 RECON BIT' } {'BAB'} 2005 2013 4500 2.9 {'TRAN'} 166 107 {'MN107-U'} {'U'} {'BAB'} 4500 9.4 2006 {0×0 char } {'BAB'} 47 0.11 0 0 0 0 {'TRAN'} 238 {'U'} {'0+0.000'} {'0+0.302'} {'2014 BAB' } {'BAB'} 2014 2014 1400 3.4 {'TRAN'} 82.5 238 {'MN238-U'} {'U'} {'BAB'} 1400 9.3 2013 {0×0 char } {'BAB'} 293.5 0.17 0 10 20 12 {'TRAN'} 238 {'U'} {'0+0.000'} {'0+0.302'} {'2014 BAB' } {'BAB'} 2014 2014 1400 3.4 {'TRAN'} 82.5 238 {'MN238-U'} {'U'} {'BAB'} 1400 9.3 2014 {'BAB Urban'} {'BAB'} 70.5 0.09 0 0 0 0 {'TRAN'} 238 {'U'} {'0+0.000'} {'0+0.302'} {'2014 BAB' } {'BAB'} 2014 2014 1400 3.4 {'TRAN'} 82.5 238 {'MN238-U'} {'U'} {'BAB'} 1400 9.3 2015 {0×0 char } {'BAB'} 69.5 0.07 0 0 0 0 {'TRAN'} 84 {'U'} {'0+0.000'} {'0+0.353'} {'2010 MED MILL & OL'} {'BOB'} 2010 2013 4500 2.2 {'TRAN'} 200.5 84 {'MN84-U' } {'U'} {'BOB'} 4500 9.4 2009 {0×0 char } {'BAB'} 211.5 0.29 0 0 0 0 {'TRAN'} 84 {'U'} {'0+0.000'} {'0+0.353'} {'2010 MED MILL & OL'} {'BOB'} 2010 2013 4500 2.2 {'TRAN'} 200.5 84 {'MN84-U' } {'U'} {'BOB'} 4500 9.4 2010 {'Med M&OL' } {'BAB'} 135 0.15 0 0 0 0 {'TRAN'} 84 {'U'} {'0+0.000'} {'0+0.353'} {'2010 MED MILL & OL'} {'BOB'} 2010 2013 4500 2.2 {'TRAN'} 200.5 84 {'MN84-U' } {'U'} {'BOB'} 4500 9.4 2011 {0×0 char } {'BAB'} 119.5 0.1 0 22 0 0 {'TRAN'} 371 {'D'} {'0+0.000'} {'0+0.375'} {'96 SURF/01 R&S' } {'BOB'} 2011 2017 53000 3 {'TRAN'} 102.5 371 {'MN371-D'} {'D'} {'BOB'} 53000 7.9 2010 {0×0 char } {'BAB'} 196.5 0.23 0 24 14 4 {'TRAN'} 371 {'D'} {'0+0.000'} {'0+0.375'} {'96 SURF/01 R&S' } {'BOB'} 2011 2017 53000 3 {'TRAN'} 102.5 371 {'MN371-D'} {'D'} {'BOB'} 53000 7.9 2011 {'Med M&OL' } {'BAB'} 39.5 0 0 0 0 0 {'TRAN'} 371 {'D'} {'0+0.000'} {'0+0.375'} {'96 SURF/01 R&S' } {'BOB'} 2011 2017 53000 3 {'TRAN'} 102.5 371 {'MN371-D'} {'D'} {'BOB'} 53000 7.9 2012 {0×0 char } {'BAB'} 73 0 0 0 0 0 {'TRAN'}

2 comentarios

Sanley Guerrier
Sanley Guerrier el 22 de Oct. de 2023
Thank you, Voss.
This is exactly what I wanted.
Voss
Voss el 22 de Oct. de 2023
You're welcome!

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