Align xticklabels along horizontal line

Hello,
I have this bar chart, and I need that the xticklabels (the days) have to be aligned along horizontal line. I need, that the days start at the same horizontal line. The days are defined as categorical values:
Xday1=categorical({'Jan.3','Jan.4','Jan.12','Jan.13','Feb.23','Feb.24','Mar.1','Mar.2','Apr.6', ...
'Jun.12','Jun.16','Jul.12','Jul.13','Oct.5','Oct.27','Oct.28','Oct.29','Nov.19','Nov.20'});
Xday1=reordercats(Xday1,{'Jan.3','Jan.4','Jan.12','Jan.13','Feb.23','Feb.24','Mar.1','Mar.2','Apr.6', ...
'Jun.12','Jun.16','Jul.12','Jul.13','Oct.5','Oct.27','Oct.28','Oct.29','Nov.19','Nov.20'});
Also, I need to double or triple the bar width, but when I set the bar widths to 2, the bars start ovelapping.
Any help would be appreciated.
Petr

4 comentarios

Dyuman Joshi
Dyuman Joshi el 23 de Oct. de 2023
It would be better if you can attach all the relevant code used to produce the bar chart and things related to it.
Okay, here is the code for the figure:
Xday1=categorical({'Jan.3','Jan.4','Jan.12','Jan.13','Feb.23','Feb.24','Mar.1','Mar.2','Apr.6', ...
'Jun.12','Jun.16','Jul.12','Jul.13','Oct.5','Oct.27','Oct.28','Oct.29','Nov.19','Nov.20'});
Xday1=reordercats(Xday1,{'Jan.3','Jan.4','Jan.12','Jan.13','Feb.23','Feb.24','Mar.1','Mar.2','Apr.6', ...
'Jun.12','Jun.16','Jul.12','Jul.13','Oct.5','Oct.27','Oct.28','Oct.29','Nov.19','Nov.20'});
figure (1)
b1=bar(Xday1,[itcs20usek1(1) itcs40usek1(1) itcs60usek1(1) itcs80usek1(1); itcs20usek2(1) itcs40usek2(1) itcs60usek2(1) itcs80usek2(1); ... 1, 2
itcs20usek14(1) itcs40usek14(1) itcs60usek14(1) itcs80usek14(1); itcs20usek15(1) itcs40usek15(1) itcs60usek15(1) itcs80usek15(1); ... 14, 15
itcs20usek3(1) itcs40usek3(1) itcs60usek3(1) itcs80usek3(1); itcs20usek4(1) itcs40usek4(1) itcs60usek4(1) itcs80usek4(1); ... 3, 4
itcs20usek16(1) itcs40usek16(1) itcs60usek16(1) itcs80usek16(1); itcs20usek5(1) itcs40usek5(1) itcs60usek5(1) itcs80usek5(1); ... 16, 5
itcs20usek6(1) itcs40usek6(1) itcs60usek6(1) itcs80usek6(1); itcs20usek7(1) itcs40usek7(1) itcs60usek7(1) itcs80usek7(1); ... 6, 7
itcs20usek8(1) itcs40usek8(1) itcs60usek8(1) itcs80usek8(1); itcs20usek9(1) itcs40usek9(1) itcs60usek9(1) itcs80usek9(1); ... 8, 9
itcs20usek10(1) itcs40usek10(1) itcs60usek10(1) itcs80usek10(1); itcs20usek11(1) itcs40usek11(1) itcs60usek11(1) itcs80usek11(1); ... 10, 11
itcs20usek21(1) itcs40usek21(1) itcs60usek21(1) itcs80usek21(1); itcs20usek22(1) itcs40usek22(1) itcs60usek22(1) itcs80usek22(1); ... 21, 22
itcs20usek23(1) itcs40usek23(1) itcs60usek23(1) itcs80usek23(1); ... 23
itcs20usek12(1) itcs40usek12(1) itcs60usek12(1) itcs80usek12(1); itcs20usek13(1) itcs40usek13(1) itcs60usek13(1) itcs80usek13(1)]); % 12, 13
Unrecognized function or variable 'Xday1'.
b1(1).FaceColor = [0 0 0]; b1(2).FaceColor = [1 1 1];
b1(3).FaceColor = [.5 .5 .5]; b1(4).FaceColor = [.25 .25 .25];
ylabel('$\sigma_u/u*$','Interpreter','latex'); % xlabel('day');
leg=legend('H=20m','H=40m','H=60m','H=80m');
set(leg,'interpreter','latex'); legend('boxoff');
ylim([0 4]); ax=gca; ax.FontSize=14;
Dyuman Joshi
Dyuman Joshi el 23 de Oct. de 2023
What are the variables used in the call to bar()? Provide the values for them as well.
Also, why are you dynamically naming variables?
Petr Michalek
Petr Michalek el 23 de Oct. de 2023
I am sorry, but you are asking for something completely different than I was asking. If you want to recreate my chart (sort of), just give to the variables some random numbers. I wanted to know how to align the Xtick Labels.

Iniciar sesión para comentar.

Respuestas (1)

In theory...
labels = {'123', '1234', '12345678'};
ax = gca;
bar(ax, [3 5 7])
xticks(ax, 1:3)
xlim(ax, [0 4])
xticklabels(ax, labels)
xtickangle(ax, 90)
drawnow(); %needed or TickLabelChild will be empty
ax.XAxis.TickLabelChild.HorizontalAlignment = 'right'; %left center right
ax.XAxis.TickLabelChild.VerticalAlignment = 'bottom'; %top middle bottom
You can see in practice it does not work

Categorías

Más información sobre Discrete Data Plots en Centro de ayuda y File Exchange.

Productos

Versión

R2022b

Preguntada:

el 23 de Oct. de 2023

Respondida:

el 23 de Oct. de 2023

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by