# problem with numerical derivative using gradient function

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Kobi on 15 Apr 2015
Commented: Michael M on 30 Apr 2020
while using gradient i encounter a phenomenon that i cannot explain, as you can see from the example below
a=[1 2 7 9;
9 8 4 1;
1 2 3 7]
ans =
1.0000 3.0000 3.5000 2.0000
-1.0000 -2.5000 -3.5000 -3.0000
1.0000 1.0000 2.5000 4.0000
i get this weird 3.5 value that is not expected all i need's a simple derivative that subtract one value with another similar to the diff function where i get this result
a=[1 2 7 9;
9 8 4 1;
1 2 3 7]
diff(a)
ans =
8 6 -3 -8
-8 -6 -1 6
the problem with diff is that i don't get the same matrix size

Star Strider on 15 Apr 2015
Youâ€™re only getting half the information that gradient is calculating.
Use this to get the gradient in the default (horizontal, along rows) direction as well as the vertical (along columns) direction:
The diff function takes the difference in the first dimension >1 by default. (You can specify a different dimension as the third argument.) So if a matrix, it will take the differences between rows (along columns) by default.
So if you want the output of gradient to correspond with the default output of diff, use the second output of gradient, here â€˜dadyâ€™ in my code.
Michael M on 30 Apr 2020
I agree. Furthermore gradient calculates mean values of neighbouring differences. That is why you get a .5 value. All is written in the doc.

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