Illegal use of reserved keyword "elseif" keep showing up?

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mohammad
mohammad el 9 de Nov. de 2023
Comentada: mohammad el 9 de Nov. de 2023
function isortvector
A = [9 -7 8 4 -3 7]
inp = input("enter 0 for ascendig && 1 for decending");
ascending = [];
descendig = [];
if inp == '0'
for i = 1:6
x = A(1);
for j=1:length(A)
if A(j) < x
x=A(j);
end
end
ascending(end+1)=x; A(A==x)=[];
end
disp("Ascending:"); disp(ascending)
end
elseif inp =='1'
for i = 1:6
x=A(1);
for j=1:length(A)
if A(j) > x
x = A(j);
end
descending(end+1) = x; A(A==x)=[];
end
disp("Descending:");
disp(descendig)
disp("uncorect input:")
disp(A)
end
end
[SL: formatted code as code]
  1 comentario
Stephen23
Stephen23 el 9 de Nov. de 2023
Editada: Stephen23 el 9 de Nov. de 2023
Note that as you have called it INPUT will return numeric values. If you expect characters (as you show use with IF and ELSEIF) then you will need to use the 's' option:
inp = input("enter 0 for ascendig && 1 for decending","s");
% ^^^
You also have to fix the names of some variables.

Iniciar sesión para comentar.

Respuesta aceptada

Stephen23
Stephen23 el 9 de Nov. de 2023
Editada: Stephen23 el 9 de Nov. de 2023
If you align your code consistently then the problem is very clear:
if inp == '0'
..
end % <- delete this
elseif inp =='1'
..
end
Tip: to align code automatically select all of your code and press ctrl+i.

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