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Solving a complex system of differential equations

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Ali Almakhmari
Ali Almakhmari el 15 de Nov. de 2023
Comentada: Torsten el 15 de Nov. de 2023
I have a this differential equation system: , where F is a function of time (t). But I am not sure whats the easiest way to solve it in MATLAB. Lets say for example:
M = [1,0.8;0.8,7]
K = [5,0;0,10]
D = [0.15,0;0,0.35]
F = [5*exp(i*5*t); 3.65*exp(i*5*t)]
q = [X; Y]
And we want to solve for q, which is X and Y.

Respuesta aceptada

Torsten
Torsten el 15 de Nov. de 2023
Editada: Torsten el 15 de Nov. de 2023
%q(1) = X, q(2) = Y, q(3) = Xdot, q(4) = Ydot
M = [1,0.8;0.8,7];
K = [5,0;0,10];
D = [0.15,0;0,0.35];
F = @(t)[5*exp(i*5*t); 3.65*exp(i*5*t)] ;
tspan = [0 1];
q0 = [0 1 1 0].';
fun = @(t,q)[[q(3);q(4)];inv(M)*(F(t)-(1i*D+K)*[q(1);q(2)])];
[T,Q] = ode45(fun,tspan,q0);
figure(1)
hold on
plot(T,real(Q(:,1)))
plot(T,imag(Q(:,1)))
hold off
figure(2)
hold on
plot(T,real(Q(:,2)))
plot(T,imag(Q(:,2)))
hold off
  2 comentarios
Ali Almakhmari
Ali Almakhmari el 15 de Nov. de 2023
Is the first plot for q(1) and q(2) or is it for q(3) and q(4)? Because the definition of fun makes me think its q(3) and q(4)
Torsten
Torsten el 15 de Nov. de 2023
The first plot is for the real and imaginary part of q(1) = X, the second plot is for the real and imaginary part of q(2) = Y.
q(3) and q(4) are Xdot and Ydot, respectively (as written in the headline of the code).

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