why the real matrix becomes complex number when transfered to cell
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why the real matrix becomes complex number when transfered to cell?
many thanks to all !
This is all of my code operations. FD is a matrix with all real number.
I actually want to get the result of fincost, but I found that the final output (fin_cost andTermfin_cost)contained complex numbers.
I use the code “isreal” to distinguish and finally find that FY contains complex numbers.
please help me see what the problem is.
Thanks to all !!
S=67
N=45% I'm sorry for a mistake that S and N are equal to 67 and 45 repectively.
FY=cell(S,S)
for i=1:1:S
for j=1:1:S
FY{i,j}=FD((i-1)*N+1:i*N,j)
end
end
containsComplex=~isreal(FY);
if containsComplex
disp('complex。');
else
disp('real。');
end
FY_shape=cell(S,S)
for i=1:1:S
for j=1:1:S
FY_shape{i,j}=FY{i,j}(1:44)
end
end
fin_cost=cell(S,1)
for i=1:1:S
fin_cost{i,1}=zeros(44,1)
for j=1:1:S
term3=FY_shape{i,i}.*FY_shape{j,j}
term4=FY_shape{i,j}.^2
term4(term4 == 0)=epsilon;
fin_cost{i,1}=fin_cost{i,1}+(term3./term4).^(1/14)
end
end
Termfin_cost= cell2mat(fin_cost)
3 comentarios
Walter Roberson
el 29 de Nov. de 2023
We recommend that you do not use i or j for loop control variables, as those are both also sqrt(-1)
Dyuman Joshi
el 29 de Nov. de 2023
There does not seem to be any complex number in the final output.
All values stored in the cell array are real, see below -
load('FD.mat');
%Check for values in FD
all(isreal(FD), 'all')
S=45;
N=6;
FY=cell(S,S);
for i=1:1:S
for j=1:1:S
FY{i,j}=FD((i-1)*N+1:i*N,j);
end
end
FY
%Check for values in FY
all(cellfun(@(x) all(isreal(x)), FY), 'all')
Respuestas (1)
Chunru
el 29 de Nov. de 2023
You won't get complex output if FD is real. Check type of FD.
S=15; %smaller
N=6;
FD = rand(N*S, S);
FY=cell(S,S)
for i=1:1:S
for j=1:1:S
FY{i,j}=FD((i-1)*N+1:i*N,j);
end
end
FY
whos
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