how to code a sum of function in matlab

I have already did a code for this function but without sum it didnt give me the right result
clear
el= 0.3;
L= 0.57 ;
h= 0.15;
t=0:0.5:20;
x=0.02;
omega1=6.0578;
omega=6.66358;
g=9.81;
A=0.0333179;
k=((1/L)*pi);
D=4*omega/L*cosh(k*h)*(1/k^(2));
C=omega*D*pi/((omega1)^(2)-(omega)^(2));
A1=-C*(D/omega);
z=(1/g)*sin(k*(x-(L/2)))*cosh(k*h)*(-A*omega1*sin(omega1*t)-C*omega*sin(omega*t))-1/g*A*omega*(x-L/2)*sin(omega*t) ;
figure
plot(t,z);

1 comentario

Dyuman Joshi
Dyuman Joshi el 1 de Dic. de 2023
The value of k is dependent on n, whereas you have defined it as a constant.
Thus, other subsequent definitions are incorrect.
And the summation is w.r.t n, whereas you are performing it w.r.t t.

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 Respuesta aceptada

Torsten
Torsten el 29 de Nov. de 2023
Movida: Torsten el 29 de Nov. de 2023

1 voto

Generate the elements that you want to sum in a matrix M of size (N,nt) where N is the index up to which you want to sum and nt is the number of time points in the "t" array. After you did this, use sum(M,1) to build the sum over the rows of M.

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