How can I speed up this function? #vectorize

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Fredrik P
Fredrik P el 12 de En. de 2024
Editada: Fredrik P el 14 de En. de 2024
I'm struggling to speed up the code inside the version1 function. The only way to vectorize it that I can seem to figure out is version2, but that actually makes the function slower. Help would be much appreciated :-)
n1 = 400;
n2 = 3;
n3 = 7;
n4 = 2;
A = rand(n1, n2, n3);
B = randi(n2, [n4, n1, n3]);
disp(timeit(@() version1(A, B, C, n1, n2, n3, n4)));
disp(timeit(@() version2(A, B, C, n1, n2, n3, n4)));
function C = version1(A, B, n1, n2, n3, n4)
C = zeros(n4, n1, n3);
for ii = 1:n3
for jj = 1:n1
for kk = 1:n4
C(kk, jj, ii) = A( ...
jj, ...
B(kk, jj, ii), ...
ii ...
);
end
end
end
end
function C = version2(A, B, n1, n2, n3, n4)
C = zeros(n4, n1, n3);
for ii = 1:n3
for jj = 1:n1
C(:, jj, ii) = A( ...
jj, ...
B(:, jj, ii), ...
ii ...
);
end
end
end

Respuesta aceptada

Matt J
Matt J el 12 de En. de 2024
Editada: Matt J el 13 de En. de 2024
I doubt a vectorized solution would be faster than the loop, but here is one way to vectorize it.
[K,J,I]=ndgrid(1:n4,1:n1,1:n3); %Recycle this, if possible
Bvals=B(sub2ind(size(B),K,J,I));
C=A( sub2ind(size(A), J,Bvals,I ));
  4 comentarios
Matt J
Matt J el 13 de En. de 2024
Editada: Matt J el 13 de En. de 2024
No, I would do this instead:
function C = version3(A, B, n1, n2, n3, n4)
[K,J,I]=ndgrid(1:n4,1:n1,1:n3); %Recycle this, if possible
Bvals=B(sub2ind(size(B),K,J,I));
C=A( sub2ind(size(A), J,Bvals,I ));
end
It doesn't matter though. Surely you've found by now that the for-loop is fastest.
Fredrik P
Fredrik P el 13 de En. de 2024
Editada: Fredrik P el 14 de En. de 2024
For me, your latest code is a lot faster. Perhaps it comes down to my actual data not being random. But more likely, the code I initially posted was a bit unfair. There, I preallocated the C matrix, but the preallocation really ought be done inside function version1 and version2, as your version3 does not need any preallocation. Also, there is not really just one A matrix and one C matrix, but rather three of each: A1, A2, and A3 and C1, C2, and C3, which all can use a variable indices=sub2ind(size(A), J,Bvals,I ). Perhaps I was too eager to minimize my minimal working example :-/

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Más respuestas (1)

Hassaan
Hassaan el 12 de En. de 2024
It seems that the complexity of the indexing in this specific case is not easily amenable to vectorization without encountering shape mismatches or broadcasting issues.it might be more practical to focus on optimizing the original loop-based implementations (version1 and version2). Often, the simplest solution can be the most efficient, especially if the code is already quite optimized and the overhead of additional complexity does not lead to significant performance gains.
If performance is critical, and these functions are a bottleneck in your application, you might consider other strategies, such as:
  1. Profiling: Use MATLAB's built-in profiling tools to identify the exact bottlenecks in your code.
  2. Parallel Computing: If you have access to MATLAB's Parallel Computing Toolbox, you might gain performance by distributing some of these operations across multiple cores or GPUs.
  3. Compiled Languages: For the most intensive computational tasks, rewriting the critical parts in a compiled language like C++ and integrating it with MATLAB might be beneficial.
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